ÌâÄ¿ÄÚÈÝ
½«Ò»¶¨ÖÊÁ¿µÄMgºÍAlµÄ»ìºÏÎïͶÈë2.0mol/L£¬250 mLÏ¡ÁòËáÖУ¬¹ÌÌåÈ«²¿ÈܽⲢ²úÉúÆøÌå¡£´ý·´Ó¦ÍêÈ«ºó£¬ÏòËùµÃÈÜÒºÖмÓÈëNaOHÈÜÒº£¬Éú³É³ÁµíµÄÎïÖʵÄÁ¿Óë¼ÓÈëNaOHÈÜÒºµÄÌå»ý¹ØÏµÈçÓÒͼËùʾ¡£ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©
A£®µ±¼ÓÇâÑõ»¯ÄÆÈÜÒºÌå»ýΪ20mLʱ£¬ÈÜÒºµÄpHÖµµÈÓÚ7
B£®µ±¼ÓÇâÑõ»¯ÄÆÈÜÒºÌå»ýΪ20mLʱ£¬ÈÜÒºÖеÄÈÜÖÊÖ»ÓÐÁòËáþºÍÁòËáÂÁ
C£®NaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ5 mol/L
D£®Éú³ÉµÄH2ÔÚ±ê×¼×´¿öϵÄÌå»ýΪ11.2 L
C
½âÎö:ÓÉͼÏóÖªn(Mg)£½n[Mg(OH)2]£½0.15 mol
¹Êm(Mg)£½0.15 mol¡Á24 g¡¤mol£1£½3.6 g
Èܽâ0.20 mol Al(OH)3ºÄNaOHµÄÎïÖʵÄÁ¿¿ÉÓÉÒÔÏ»¯Ñ§·½³Ìʽ¼ÆËã
Al(OH)3£«NaOH===Na[Al(OH)4]
£½
c(NaOH)£½5 mol/L¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
| A¡¢MgºÍAlµÄ×ÜÖÊÁ¿Îª9g | B¡¢Éú³ÉµÄH2ÔÚ±ê×¼×´¿öϵÄÌå»ýΪ11.2L | C¡¢NaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ5mol/L | D¡¢ÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ1mol/L |