ÌâÄ¿ÄÚÈÝ

ÏÖÓÐÒ»°ü¹ÌÌå·ÛÄ©£¬ÆäÖпÉÄܺ¬ÓÐCaCO3¡¢Na2CO3¡¢Na2SO4¡¢NaCl¡¢CuSO4£®½øÐÐÈçÏÂʵÑ飺¢ÙÈÜÓÚË®µÃÎÞÉ«ÈÜÒº£»¢ÚÏòÈÜÒºÖмÓÈëBaCl2ÈÜÒºÉú³É°×É«³Áµí£¬ÔÙ¼ÓÑÎËáʱ³Áµí²¿·ÖÈܽ⣮¸ù¾ÝÉÏÊöʵÑéÏÖÏóÍÆ¶Ï£º

(1)Ò»¶¨²»´æÔÚµÄÎïÖÊÊÇ________£»

(2)Ò»¶¨´æÔÚµÄÎïÖÊÊÇ________£»

(3)¿ÉÄÜ´æÔÚµÄÎïÖÊÊÇ________£»

(4)¶ÔÓÚ¿ÉÄÜ´æÔÚµÄÎïÖʵļìÑé·½·¨ÊÇ(д³ö¼òÒª²½ÖèºÍÓйصÄÀë×Ó·½³Ìʽ)________________£®

´ð°¸£º
½âÎö£º

¡¡¡¡(1)CuSO4£¬CaCO3

¡¡¡¡(2)Na2SO4£¬Na2CO3

¡¡¡¡(3)NaCl

¡¡¡¡(4)È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏȼÓÈë×ãÁ¿µÄÏ¡ÏõËáËữ£¬ÔÙ¼ÓÈëAgNO3ÈÜÒº£¬Èô²úÉú°×É«³Áµí£¬Ôò˵Ã÷º¬NaCl¡¡ÂÔ


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2012?õ·ÁêÊÐÄ£Ä⣩ʵÑéÊÒÓÐÒ»°ü°µºìÉ«·ÛÄ©ÑùÆ·¿ÉÄÜÊÇCaCO3¡¢Fe2O3»òFeOµÄ»ìºÏÎºó¾­²â¶¨ÒÑÈ·¶¨²»´æÔÚFeO£®
I£®Ä³Ñ§ÉúÏë×Ô¼ºÉè¼ÆÊµÑé·½°¸£¬ÒÔÖ¤Ã÷ÑùÆ·ÖÐȷʵûÓÐFeO£®³ýÑùÆ·Í⣬ʵÑéÊÒÖ»ÌṩÒÔÏÂÊÔ¼Á£ºKMnO4ÈÜÒº¡¢Ï¡ÑÎËᡢϡÁòËá¡¢KSCNÈÜÒº¡¢NaOHÈÜÒººÍË«ÑõË®£®ÄãÈÏΪҪÍê³É¸ÃʵÑéËùÑ¡ÔñµÄÊÔ¼ÁÊÇ
KMnO4ÈÜÒº¡¢Ï¡ÁòËá
KMnO4ÈÜÒº¡¢Ï¡ÁòËá
£¬ÇëÄãÃèÊöʵÑé²Ù×÷ʱµÄ²½Ö衢ʵÑéÏÖÏóºÍ½áÂÛ£º
È¡ÉÙÁ¿ÑùÆ·ÈÜÓÚÊÔ¹ÜÖУ¬Åä³ÉÈÜÒººó£¬ÔÙµÎÈ뼸µÎÏ¡ÁòËáºÍ¼¸µÎKMnO4ÈÜÒº£¬Ö»ÒªÈÜÒº²»ÍÊÉ«»ò²»±ädz£¬¼´ËµÃ÷ÑùÆ·ÖÐÎÞFeO
È¡ÉÙÁ¿ÑùÆ·ÈÜÓÚÊÔ¹ÜÖУ¬Åä³ÉÈÜÒººó£¬ÔÙµÎÈ뼸µÎÏ¡ÁòËáºÍ¼¸µÎKMnO4ÈÜÒº£¬Ö»ÒªÈÜÒº²»ÍÊÉ«»ò²»±ädz£¬¼´ËµÃ÷ÑùÆ·ÖÐÎÞFeO
£®
¢ò£®²â¶¨»ìºÏÎïÖÐFe2O3µÄº¬Á¿
ʵÑéÊÒ¿ÉÓöàÖÖ·½·¨²â³öÉÏÊöÑùÆ·ÖÐFe2O3µÄÖÊÁ¿·ÖÊý£®ÏÖÓÐѧÉú×¼±¸ÓÃÈçͼ¸÷×°Öð´Ò»¶¨Ë³ÐòÁ¬½Ó³ÉÒ»Ì×ÍêÕûµÄ×éºÏ×°ÖÃÀ´½øÐÐʵÑéÒԲⶨFe2O3µÄÖÊÁ¿·ÖÊý£®

Çë¸ù¾ÝÌâÒâ»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°ÖõÄÁ¬½Ó˳ÐòÊÇ
BDAC
BDAC
£¨Ìî×Öĸ£¬Ã¿¸ö×°ÖÃÖ»ÄÜÓÃÒ»´Î£©
£¨2£©ÊµÑé¹ý³ÌÖÐÐèÒª³ÖÐøÍ¨Èë¿ÕÆø£¬Æä×÷Óóý¿ÉÒÔÆðµ½¡°½Á°è¡±A¡¢DÖз´Ó¦Îï´ïµ½³ä·Ö·´Ó¦Í⣬»¹ÓÐÒ»¸öÖØÒª×÷ÓÃÊÇ
½«·´Ó¦²úÉúµÄCO2ÆøÌ御¿ÉÄܳ¹µ×µÄ¸ÏÈë×°ÖÃAÖУ¬Ê¹Ö®ÍêÈ«±»Ba£¨OH£©2ÈÜÒºÎüÊÕ
½«·´Ó¦²úÉúµÄCO2ÆøÌ御¿ÉÄܳ¹µ×µÄ¸ÏÈë×°ÖÃAÖУ¬Ê¹Ö®ÍêÈ«±»Ba£¨OH£©2ÈÜÒºÎüÊÕ

£¨3£©ÏÂÁи÷Ïî´ëÊ©ÖУ¬ÄÜÌá¸ß²â¶¨×¼È·¶ÈµÄÊÇ
ad
ad
 £¨Ìî±êºÅ£©
a£®ÔÚ¼ÓÈëÑÎËá֮ǰ£¬Ó¦¸ÃÅž¡×°ÖÃÄÚµÄCO2ÆøÌå
b£®¿ìËÙ¼ÓÈëÑÎËá
c£®ÔÚBÖÐ×°ÈëŨÁòËá
d£®ÔÚBÖÐ×°ÈëNaOHÈÜÒº
e£®DÖ®ºóÔöÌíÊ¢Óб¥ºÍ̼ËáÇâÄÆÈÜÒºµÄÏ´Æø×°ÖÃ
£¨4£©ÊµÑéÊÒ׼ȷ³ÆÈ¡26.0g¹ÌÌåÑùÆ·×°ÈëDÖУ¬³ä·Ö·´Ó¦ºó£¬²âµÃAÖгÁµíÖÊÁ¿Îª19.7g£¬ÔòÑùÆ·ÖÐFe2O3µÄÖÊÁ¿·ÖÊýΪ
61.5%
61.5%
£®
£¨5£©ÔÚ½øÐÐʵÑé·½°¸ÆÀ¼Ûʱ£¬ÓÐѧÉúÈÏΪ²»±Ø²â¶¨AÖеijÁµíÖÊÁ¿£¬¶øÖ»Òª²â³ö×°ÖÃAÔÚÎüÊÕ·´Ó¦²úÉúµÄÆøÌåǰºóµÄÖÊÁ¿²î£¬¾ÍÄÜÍê³ÉʵÑéÒªÇó£®ÊµÑéÖ¤Ã÷£¬ÈôÓô˷¨²âµÃFe2O3µÄÖÊÁ¿·ÖÊý½«
Æ«µÍ
Æ«µÍ
£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±¡¢¡°²»±ä¡±£©
ÄÆ¡¢Ã¾¡¢ÂÁ¡¢ÌúµÈ½ðÊôÔÚÈÕ³£Éú»î¡¢¹¤ÒµÉú²ú¡¢º½ÌìÊÂÒµÖÐÓÐ׏㷺µÄÓÃ;£®
£¨1£©4.8gAlÔÚ¿ÕÆøÖзÅÖÃÒ»¶Îʱ¼äÖ®ºó£¬ÖÊÁ¿±äΪ5.28g£¬Ôòδ·¢Éú±ä»¯µÄÂÁµÄÖÊÁ¿Îª
 
g£®
£¨2£©Ïò10mL 0.2mol/LµÄÂÈ»¯ÂÁÈÜÒºÖÐÖðµÎ¼ÓÈëδ֪Ũ¶ÈµÄÇâÑõ»¯±µÈÜÒº£¬²âµÃµÎ¼Ó10mLÓëµÎ¼Ó30mLʱËùµÃ³ÁµíÒ»Ñù¶à£®ÇóÇâÑõ»¯±µÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È£®
£¨3£©½«Ã¾¡¢ÂÁºÏ½ð6.3g»ìºÏÎï¼ÓÈ뵽ijŨ¶ÈµÄÏõËáÖУ¬²úÉú±ê¿öÏÂµÄÆøÌå8.96L£¨¼ÙÉè·´Ó¦¹ý³ÌÖл¹Ô­²úÎïÊÇNOºÍNO2µÄ»ìºÏÆøÌ壩£¬ÏòËùµÃÈÜÒºÖмÓÈ백ˮÖÁ³Áµí´ïµ½×î´óÁ¿£¬³Áµí¸ÉÔïºó²âµÃµÄÖÊÁ¿±ÈÔ­ºÏ½ðµÄÖÊÁ¿Ôö¼Ó10.2g£¬¼ÆË㻹ԭ²úÎïÖÐNOºÍNO2µÄÎïÖʵÄÁ¿Ö®±È£®
£¨4£©ÏÖÓÐÒ»°üÂÁÈȼÁÊÇÂÁ·ÛºÍÑõ»¯Ìú·ÛÄ©µÄ»ìºÏÎÔÚ¸ßÎÂÏÂʹ֮³ä·Ö·´Ó¦£¬½«·´Ó¦ºóµÄ¹ÌÌå·ÖΪÁ½µÈ·Ý£¬½øÐÐÈçÏÂʵÑ飨¼ÆËãpHʱ¼Ù¶¨ÈÜÒºÌå»ýûÓб仯£©£º¢ÙÏòÆäÖÐÒ»·Ý¹ÌÌåÖмÓÈë50mL 3.0mol/LµÄNaOHÈÜÒº£¬¼ÓÈÈʹÆä³ä·Ö·´Ó¦ºó¹ýÂË£¬²âµÃÂËÒºµÄc£¨OH-£©Îª1.0mol/L£»¢ÚÏòÁíÒ»·Ý¹ÌÌåÖмÓÈë100mL 4.0mol/LµÄHClÈÜÒº£¬Ê¹¹ÌÌåÈ«²¿Èܽ⣬²âµÃ·´Ó¦ºóËùµÃÈÜÒºÖÐÖ»ÓÐH+¡¢Fe2+ºÍAl3+ÈýÖÖÑôÀë×ÓÇÒc£¨H+£©Îª0.2mol/L£¬¼ÆËãÕâ°üÂÁÈȼÁÖÐÂÁµÄÖÊÁ¿ºÍÑõ»¯ÌúµÄÖÊÁ¿£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø