ÌâÄ¿ÄÚÈÝ

£¨10·Ö£¬Ã¿¿Õ2·Ö£©¼×¡¢ÒÒÁ½¸öʵÑéС×éÀûÓÃKMnO4ËáÐÔÈÜÒºÓëH2C2O4ÈÜÒº·´Ó¦Ñо¿Ó°Ïì·´Ó¦ËÙÂʵÄÒòËØ¡£
£¨1£©¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ£¨Ìáʾ£ºH2C2O4µÄÒ»¼¶µçÀëÆ½ºâ³£ÊýΪ5.4¡Á10-2£©
                                                                        ¡£
Éè¼ÆÊµÑé·½°¸ÈçÏ£¨ÊµÑéÖÐËùÓÃKMnO4ÈÜÒº¾ùÒѼÓÈëH2SO4£©£º
£¨2£©¼××飺ͨ¹ý²â¶¨µ¥Î»Ê±¼äÄÚÉú³ÉCO2ÆøÌåÌå»ýµÄ´óСÀ´±È½Ï»¯Ñ§·´Ó¦ËÙÂʵĴóС¡£ÊµÑé×°ÖÃÈçͼ£¬ÊµÑéʱ·ÖҺ©¶·ÖÐAÈÜÒºÒ»´ÎÐÔ·ÅÏ£¬A¡¢BµÄ³É·Ö¼ûÏÂ±í£º

ÐòºÅ
AÈÜÒº
BÈÜÒº
¢Ù
2 mL 0.1 mol/L H2C2O4ÈÜÒº
4 mL 0.01 mol/L KMnO4ÈÜÒº
¢Ú
2 mL 0.2 mol/L H2C2O4ÈÜÒº
4 mL 0.01 mol/L KMnO4ÈÜÒº
¢Û
2 mL 0.2 mol/L H2C2O4ÈÜÒº
4 mL 0.01 mol/L KMnO4ÈÜÒººÍÉÙÁ¿MnSO4
¸ÃʵÑé̽¾¿µÄÊÇ            ¶Ô»¯Ñ§·´Ó¦ËÙÂʵÄÓ°Ïì¡£ÔÚ·´Ó¦Í£Ö¹Ö®Ç°£¬Ïàͬʱ¼äÄÚÕë¹ÜÖÐËùµÃCO2µÄÌå»ýÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ               (ÓÃʵÑéÐòºÅÌî¿Õ)¡£
£¨3£©ÒÒ×飺ͨ¹ý²â¶¨KMnO4ÈÜÒºÍÊÉ«ËùÐèʱ¼äµÄ¶àÉÙÀ´±È½Ï»¯Ñ§·´Ó¦ËÙÂʵĴóС¡£
È¡Á½Ö§ÊԹܸ÷¼ÓÈë2 mL 0.1 mol/L H2C2O4ÈÜÒº£¬ÁíÈ¡Á½Ö§ÊԹܸ÷¼ÓÈë4 mL 0.1 mol/L KMnO4ÈÜÒº¡£½«ËÄÖ§ÊԹֳܷÉÁ½×飨¸÷ÓÐÒ»Ö§Ê¢ÓÐH2C2O4ÈÜÒººÍKMnO4ÈÜÒºµÄÊԹܣ©£¬Ò»×é·ÅÈëÀäË®ÖУ¬ÁíÒ»×é·ÅÈëÈÈË®ÖУ¬¾­¹ýÒ»¶Îʱ¼äºó£¬·Ö±ð»ìºÏ²¢Õñµ´£¬¼Ç¼ÈÜÒºÍÊÉ«ËùÐèʱ¼ä¡£¸ÃʵÑéÄ¿µÄÊÇÑо¿              ¶Ô»¯Ñ§·´Ó¦ËÙÂʵÄÓ°Ï죬µ«¸Ã×éͬѧʼÖÕûÓп´µ½ÈÜÒºÍÊÉ«£¬ÆäÔ­ÒòÊÇ                                            ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨10·Ö£¬Ã¿¿Õ2·Ö£©ÓÒͼΪʵÑéÊÒijŨÑÎËáÊÔ¼ÁÆ¿ÉϵıêÇ©£¬ÊÔ¸ù¾ÝÓйØÊý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ä³Ñ§ÉúÓûÓÃÉÏÊöŨÑÎËáºÍÕôÁóË®ÅäÖÆ500 mLÎïÖʵÄÁ¿Å¨¶ÈΪ0.30 mol/LÏ¡ÑÎËá¡£

¢Ù¸ÃѧÉúÐèÒªÁ¿È¡        mLÉÏÊöŨÑÎËá½øÐÐÅäÖÆ¡£

¢ÚÅäÖÆÊ±£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ(ÓÃ×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î)                           ¡£

A.ÓÃ30mLˮϴµÓÉÕ±­2¡«3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬ÇáÇáÒ¡¶¯ÈÝÁ¿Æ¿

B.ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèŨÑÎËáµÄÌå»ý£¬ÂýÂýÑØ±­±Ú×¢ÈëÊ¢ÓÐÉÙÁ¿Ë®£¨Ô¼30 mL£©µÄÉÕ±­ÖУ¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä»ìºÏ¾ùÔÈ

C.½«ÒÑÀäÈ´µÄÑÎËáÑØ²£Á§°ô×¢Èë500mLµÄÈÝÁ¿Æ¿ÖÐ

D.½«ÈÝÁ¿Æ¿µÄ²£Á§Èû¸Ç½ô£¬µßµ¹Ò¡ÔÈ

E.¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐ

F.¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2cm´¦

¢ÛÔÚÅäÖÆ¹ý³ÌÖУ¬ÏÂÁвÙ×÷»áʹËùÅäÖÆµÄÏ¡ÑÎËáÎïÖʵÄÁ¿Å¨¶ÈÆ«¸ßµÄÊÇ               ¡£

A.ÓÃÁ¿Í²Á¿È¡Å¨ÑÎËáʱ¸©ÊÓ¹Û²ì°¼ÒºÃæ

B.Ò¡ÔȺó£¬ÒºÃæÏ½µ£¬²¹³äË®

C.¶¨ÈÝʱÑöÊӿ̶ÈÏß

D.ÔÚÅäÖÆÇ°ÓÃÏàͬŨ¶ÈµÄÏ¡ÑÎËáÈóÏ´ÈÝÁ¿Æ¿

£¨2£©ÏÖ½«200mL0.30mol/LµÄÑÎËáÓë50mL0.80mol/LCaCl2ÈÜÒº»ìºÏ(»ìºÏºóÌå»ý±ä»¯ºöÂÔ²»¼Æ)£¬ËùµÃÈÜÒºÖÐCl£­µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ          mol/L¡£

£¨3£©ÔÚ±ê×¼×´¿öÏ£¬½«_____________L HClÆøÌåÈÜÓÚ1000 mLË®ÖÐ(Ë®µÄÃܶÈΪ1 g/cm3)£¬ËùµÃÈÜÖÊÖÊÁ¿·ÖÊýΪ36.5%µÄÑÎËá¡£(±£ÁôСÊýµãºóһλ)

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø