ÌâÄ¿ÄÚÈÝ

19£®A¡¢B¡¢C¡¢D¾ùΪÖÐѧËùѧµÄ³£¼ûÎïÖÊÇÒ¾ùº¬ÓÐͬһÖÖÔªËØ£¬ËüÃÇÖ®¼äµÄת»¯¹ØÏµÈçÏÂͼËùʾ£¨·´Ó¦Ìõ¼þ¼°ÆäËûÎïÖÊÒѾ­ÂÔÈ¥£©£ºA$\stackrel{+O_{2}}{¡ú}$B$\stackrel{+O_{2}}{¡ú}$C$\stackrel{+HO_{2}}{¡ú}$D£®
£¨1£©ÈôA¡¢DµÄË®ÈÜÒº¾ùÄÜʹʪÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½±äºì£¬ÇÒDΪǿËᣬÔòA¡¢D·Ö±ðΪ£¨Ìîд»¯Ñ§Ê½£©A£ºH2S£¬D£ºH2SO4£®Ð´³öA¡úBת»¯µÄ»¯Ñ§·½³Ìʽ£º2H2S+3O2$\frac{\underline{\;µãȼ\;}}{\;}$2SO2+2H2O£®
£¨2£©ÈôAµÄË®ÈÜÒºÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬DµÄÏ¡ÈÜÒºÄÜʹÀ¶É«µÄʪÈóʯÈïÊÔÖ½±äºì£®ÔòAΪNH3£¬Ð´³öA¡úBת»¯µÄ»¯Ñ§·½³Ìʽ£º4NH3+5O2$\frac{\underline{´ß»¯¼Á}}{¡÷}$4NO+6H2O£®

·ÖÎö £¨1£©ÈôA¡¢DµÄË®ÈÜÒº¾ùÄÜʹʪÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½±äºì£¬ÇÒDΪǿËᣬÔòAΪH2S£¬BÊÇSO2£¬CÊÇSO3£¬DÊÇH2SO4£»
£¨2£©ÈôAµÄË®ÈÜÒºÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬DµÄÏ¡ÈÜÒºÄÜʹÀ¶É«µÄʪÈóʯÈïÊÔÖ½±äºì£¬ÔòAΪNH3£¬BΪNO£¬CΪNO2£¬DΪHNO3£®

½â´ð ½â£º£¨1£©ÈôA¡¢DµÄË®ÈÜÒº¾ùÄÜʹʪÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½±äºì£¬ÇÒDΪǿËᣬÔòAΪH2S£¬BÊÇSO2£¬CÊÇSO3£¬DÊÇH2SO4£¬A¡úBת»¯µÄ»¯Ñ§·½³Ìʽ£º2H2S+3O2$\frac{\underline{\;µãȼ\;}}{\;}$2SO2+2H2O£¬
¹Ê´ð°¸Îª£ºH2S£»H2SO4£»2H2S+3O2$\frac{\underline{\;µãȼ\;}}{\;}$2SO2+2H2O£»
£¨2£©ÈôAµÄË®ÈÜÒºÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£¬DµÄÏ¡ÈÜÒºÄÜʹÀ¶É«µÄʪÈóʯÈïÊÔÖ½±äºì£¬ÔòAΪNH3£¬BΪNO£¬CΪNO2£¬DΪHNO3£¬A¡úBת»¯µÄ»¯Ñ§·½³Ìʽ£º4NH3+5O2$\frac{\underline{´ß»¯¼Á}}{¡÷}$4NO+6H2O£¬
¹Ê´ð°¸Îª£ºNH3£»4NH3+5O2$\frac{\underline{´ß»¯¼Á}}{¡÷}$4NO+6H2O£®

µãÆÀ ±¾Ì⿼²éÔªËØ»¯ºÏÎïµÄÍÆ¶Ï£¬Éæ¼°S¡¢NÔªËØµ¥Öʼ°Æä»¯ºÏÎïÐÔÖÊÓëת»¯£¬ÐèҪѧÉúÊìÁ·ÕÆÎÕÔªËØ»¯ºÏÎï֪ʶ£¬×¢ÒâÏà¹Ø»ù´¡ÖªÊ¶µÄ»ýÀÛ£¬ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø