ÌâÄ¿ÄÚÈÝ

ÏÂͼΪÖÜÆÚ±íÖжÌÖÜÆÚµÄÒ»²¿·Ö£¬A¡¢B¡¢CÈýÔªËØÔ­×ÓºËÍâµç×ÓÊýÖ®ºÍµÈÓÚBÔªËØµÄÖÊÁ¿Êý¡£BÔ­×ÓºËÄÚÖÊ×ÓÊýºÍÖÐ×ÓÊýÏàµÈ¡£ÊԻشð£º

A

 

C

 

B

 

(1)A¡¢B¡¢CÈýÖÖÔªËØµÄÃû³Æ£ºA________£¬B________£¬C________¡£

(2)A¡¢B×î¸ß¼ÛÑõ»¯ÎïµÄ»¯Ñ§Ê½£ºA____¡¡¡¡¡¡¡¡    ___£¬B____¡¡¡¡    ____¡£

(3)A¡¢CÆøÌ¬Ç⻯ÎïµÄ»¯Ñ§Ê½£ºA______¡¡¡¡  __£¬C__¡¡¡¡    ______¡£

(4)BÔªËØÔÚÖÜÆÚ±íÖеÄλÖãº____¡¡¡¡¡¡¡¡ ¡¡¡¡ ____¡£

(5)Cµ¥ÖʸúË®·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________¡£

(6)Óõç×Óʽ·Ö±ð±íʾAµ¥ÖÊ¡¢BÔªËØµÄÆøÌ¬Ç⻯ÎïÒÔ¼°Cµ¥ÖʵÈÈýÖÖÎïÖʵĻ¯Ñ§Ê½¡£

 

´ð°¸£º
½âÎö£º

(1)µª£¬Áò£¬·ú£»

(2)N2O5£¬SO3£»

(3)NH3£¬HF

(4)µÚ3ÖÜÆÚVIA×å

(5)2F2+2H2O=4HF+O2 

(6):NN:£¬£¬

 


Ìáʾ£º

ÓÉÌâÒâ¿ÉµÃ£ºeA+eB+eC=2eBeA+eC=eBeB-8-1+ eB-8+1= 2eBeB=16£¬BΪÁò£¬AΪµª£¬CΪ·ú¡£

 


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø