ÌâÄ¿ÄÚÈÝ
ÔÚ»¯Ñ§·´Ó¦ÖУ¬Ö»Óм«ÉÙÊýÄÜÁ¿±Èƽ¾ùÄÜÁ¿¸ßµÃ¶àµÄ·´Ó¦Îï·Ö×Ó·¢ÉúÅöײʱ²Å¿ÉÄÜ·¢Éú»¯Ñ§·´Ó¦£¬ÕâЩ·Ö×Ó³ÆÎª»î»¯·Ö×Ó£¬Ê¹ÆÕͨ·Ö×Ó±ä³É»î»¯·Ö×ÓËùÐèÌṩµÄ×îµÍÏ޶ȵÄÄÜÁ¿½Ð»î»¯ÄÜ£¬Æäµ¥Î»Í¨³£ÓÃkJ/mol±íʾ¡£ÇëÈÏÕæ¹Û²ìÏÂͼ£¬È»ºó»Ø´ðÎÊÌâ¡£
![]()
£¨1£©Í¼ÖÐËùʾ·´Ó¦ÊÇ_________£¨Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©·´Ó¦£¬¸Ã·´Ó¦________£¨Ìî¡°ÐèÒª¡±»ò¡°²»ÐèÒª¡±£©¼ÓÈÈ£¬¸Ã·´Ó¦µÄ¡÷H£½___________________kJ/mol£¨Óú¬E1¡¢E2µÄ´úÊýʽ±íʾ£©¡£
£¨2£©ÒÑÖªÈÈ»¯Ñ§·½³Ìʽ£ºH2£¨g£©£« 0.5 O2£¨g£©£½H2O£¨g£©£»¡÷H£½£241.8 kJ£¯mol
¸Ã·´Ó¦µÄ»î»¯ÄÜΪ167.2 kJ£¯mol£¬ÔòÆäÄæ·´Ó¦µÄ»î»¯ÄÜΪ____________________¡£
£¨3£©¶ÔÓÚͬһ·´Ó¦£¬Í¼ÖÐÐéÏߣ¨¢ò£©ÓëʵÏߣ¨¢ñ£©Ïà±È£¬»î»¯ÄÜ´ó´ó½µµÍ£¬»î»¯·Ö×ӵİٷÖÊýÔö¶à£¬·´Ó¦ËÙÂʼӿ죬ÄãÈÏΪ×î¿ÉÄܵÄÔÒòÊÇ£º___________________________¡£
£¨1£©·ÅÈÈ ÐèÒª ¡ª£¨E1¡ªE2£©kJ/mol
£¨2£©409 kJ/mol £¨2·Ö£© £¨3£©Ê¹ÓÃÁË´ß»¯¼Á
¡¾½âÎö¡¿