ÌâÄ¿ÄÚÈÝ

£¨8·Ö£©»ÔÍ­¿ó£¨Ö÷³É·ÝΪCu2S£©Í¨ÊÊÁ¿µÄ¿ÕÆø¿ÉÒ±Á¶½ðÊôÍ­£¬¾­¹ýһϵÁз´Ó¦¿ÉµÃµ½BºÍD¡¢E¡£GΪשºìÉ«³Áµí¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©»ÔÍ­¿ó£¨Cu2S£©Í¨ÊÊÁ¿µÄ¿ÕÆøÒ±Á¶½ðÊôÍ­µÄ»¯Ñ§·½³Ìʽ__________________________

______ÆäÖÐÑõ»¯¼ÁΪ____________________¡£

£¨2£©EµÄŨÈÜÒºÓëCu·¢Éú·´Ó¦¢ÚµÄ»¯Ñ§·½³ÌʽÊÇ                              ¡£

£¨3£©ÀûÓõç½â¿ÉÌá´¿´Ö£¬Ôڸõç½â·´Ó¦ÖÐÑô¼«ÎïÖÊÊÇ        £¬µç½âÖÊÈÜÒºÊÇ         £»

£¨4£©×ÔÈ»½çÖе±µ¨·¯¿óÓë»ÆÌú¿ó£¨FeS2¶þÁò»¯ÑÇÌú£©ÏàÓöʱ»á»ºÂý·¢ÉúÏÂÁз´Ó¦²úÉú»ÔÍ­¿ó¡£¶Ô·´Ó¦£º14CuSO4+5FeS2 +12H2O==7Cu2S+5FeSO4+12H2SO4 

±»Ñõ»¯µÄÁòºÍ±»»¹Ô­µÄÁòµÄÖÊÁ¿±ÈΪ_________________________£»

 

(1) Cu2S+O2£¨ÊÊÁ¿£©  2Cu+SO2   Ñõ»¯¼Á£ºO2ºÍ Cu2S £» 

(2) Cu+2H2SO4(Ũ)CuSO4+SO2¡ü+2H2O  £»

(3) ´ÖÍ­ £»ÁòËáÍ­»òº¬Cu2+µÄÑÎÈÜÒº £»

(4)  3£º7

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø