ÌâÄ¿ÄÚÈÝ
·°(v)¼°Æä»¯ºÏÎï¹ã·ºÓ¦ÓÃÓÚ¹¤Òµ´ß»¯¡¢Ð²ÄÁϺÍÐÂÄÜÔ´µÈÁìÓò¡£
V2O5ÊǽӴ¥·¨ÖÆÁòËáµÄ´ß»¯¼Á¡£
£¨1£©Ò»¶¨Ìõ¼þÏ£¬SO2Óë¿ÕÆø·´Ó¦tminºó£¬SO2ºÍSO3ÎïÖʵÄÁ¿Å¨¶È·Ö±ðΪamol/LºÍbmol/L£¬ÔòSO2ÆðʼÎïÖʵÄÁ¿Å¨¶ÈΪ____mol/L£»Éú³ÉSO3µÄ»¯Ñ§·´Ó¦ËÙÂÊΪ____mol/(L¡¤min)¡£
£¨2£©¹¤ÒµÖÆÁòËá£¬Î²ÆøSO2ÓÃ___ÎüÊÕ¡£
È«·°ÒºÁ÷´¢ÄÜµç³ØÊÇÀûÓò»Í¬¼Û̬Àë×Ó¶ÔµÄÑõ»¯»¹Ô·´Ó¦À´ÊµÏÖ»¯Ñ§Äܺ͵çÄÜÏ໥ת»¯µÄ×°Öã¬ÆäÔÀíÈçÏÂͼËùʾ¡£
V2O5ÊǽӴ¥·¨ÖÆÁòËáµÄ´ß»¯¼Á¡£
£¨1£©Ò»¶¨Ìõ¼þÏ£¬SO2Óë¿ÕÆø·´Ó¦tminºó£¬SO2ºÍSO3ÎïÖʵÄÁ¿Å¨¶È·Ö±ðΪamol/LºÍbmol/L£¬ÔòSO2ÆðʼÎïÖʵÄÁ¿Å¨¶ÈΪ____mol/L£»Éú³ÉSO3µÄ»¯Ñ§·´Ó¦ËÙÂÊΪ____mol/(L¡¤min)¡£
£¨2£©¹¤ÒµÖÆÁòËá£¬Î²ÆøSO2ÓÃ___ÎüÊÕ¡£
È«·°ÒºÁ÷´¢ÄÜµç³ØÊÇÀûÓò»Í¬¼Û̬Àë×Ó¶ÔµÄÑõ»¯»¹Ô·´Ó¦À´ÊµÏÖ»¯Ñ§Äܺ͵çÄÜÏ໥ת»¯µÄ×°Öã¬ÆäÔÀíÈçÏÂͼËùʾ¡£
£¨3£©µ±×ó²ÛÈÜÒºÑÕÉ«Öð½¥ÓɻƱäÀ¶£¬Æäµç¼«·´Ó¦Ê½Îª____¡£
£¨4£©³äµç¹ý³ÌÖУ¬ÓÒ²ÛÈÜÒºÑÕÉ«Öð½¥ÓÉ____É«±äΪ____É«¡£
£¨5£©·Åµç¹ý³ÌÖÐÇâÀë×ÓµÄ×÷ÓÃÊÇ___ºÍ___£»³äµçʱÈô×ªÒÆµÄµç×ÓÊý Ϊ3.0l¡Á1023¸ö£¬×ó²ÛÈÜÒºÖÐn(H+)µÄ±ä»¯Á¿Îª____¡£
£¨4£©³äµç¹ý³ÌÖУ¬ÓÒ²ÛÈÜÒºÑÕÉ«Öð½¥ÓÉ____É«±äΪ____É«¡£
£¨5£©·Åµç¹ý³ÌÖÐÇâÀë×ÓµÄ×÷ÓÃÊÇ___ºÍ___£»³äµçʱÈô×ªÒÆµÄµç×ÓÊý Ϊ3.0l¡Á1023¸ö£¬×ó²ÛÈÜÒºÖÐn(H+)µÄ±ä»¯Á¿Îª____¡£
£¨1£©a+b£»b/t
£¨2£©°±Ë®
£¨3£©VO2++2H++e- = VO2++H2O
£¨4£©ÂÌ£»×Ï
£¨5£©²ÎÓëÕý¼«·´Ó¦£»Í¨¹ý½»»»Ä¤¶¨ÏòÒÆ¶¯Ê¹µçÁ÷ͨ¹ýÈÜÒº£»0.5 mol
£¨2£©°±Ë®
£¨3£©VO2++2H++e- = VO2++H2O
£¨4£©ÂÌ£»×Ï
£¨5£©²ÎÓëÕý¼«·´Ó¦£»Í¨¹ý½»»»Ä¤¶¨ÏòÒÆ¶¯Ê¹µçÁ÷ͨ¹ýÈÜÒº£»0.5 mol
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿