ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÊµÑéÊҺϳÉÒÒËáÒÒõ¥µÄ²½ÖèÈçÏ£ºÔÚÔ²µ×ÉÕÆ¿ÄÚ¼ÓÈëÒÒ´¼¡¢Å¨ÁòËáºÍÒÒËᣬƿ¿ÚÊúÖ±°²×°Í¨ÓÐÀäÈ´Ë®µÄÀäÄý¹Ü£¨Ê¹·´Ó¦»ìºÏÎïµÄÕôÆøÀäÄýΪҺÌåÁ÷»ØÉÕÆ¿ÄÚ£©£¬¼ÓÈÈ»ØÁ÷Ò»¶Îʱ¼äºó»»³ÉÕôÁó×°ÖýøÐÐÕôÁó£¨ÈçÏÂͼËùʾ£©£¬µÃµ½º¬ÓÐÒÒ´¼¡¢ÒÒËáºÍË®µÄÒÒËáÒÒõ¥´Ö²úÆ·¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
![]()
£¨ÒÑÖª£ºÒÒ´¼¡¢ÒÒËá¡¢ÒÒËáÒÒõ¥µÄ·ÐµãÒÀ´ÎÊÇ78.4¡æ¡¢118¡æ¡¢77.1¡æ£©
(1)ÔÚÉÕÆ¿ÖгýÁ˼ÓÈëÒÒ´¼¡¢Å¨ÁòËáºÍÒÒËáÍ⣬»¹Ó¦·ÅÈ뼸¿éËé´ÉƬ£¬ÆäÄ¿µÄÊÇ_____________¡£
(2)×¶ÐÎÆ¿ÖÐÓ¦¼ÓÈëÄÄÖÖÊÔ¼Á?________________£¬×÷ÓÃÊÇ__________¡£
(3)д³öÖÆÈ¡ÒÒËáÒÒõ¥µÄ»¯Ñ§·½³Ìʽ£º_____________¡£
¡¾´ð°¸¡¿ ·ÀÖ¹±©·Ð ±¥ºÍ̼ËáÄÆÈÜÒº ÈܽâÒÒ´¼£¬·´Ó¦ÒÒËᣬ½µµÍÒÒËáÒÒõ¥Èܽâ¶È CH3COOH+CH3CH2OH
CH3COOCH2CH3+H2O
¡¾½âÎö¡¿(1)ÒÒËá¡¢ÒÒ´¼·ÐµãµÍ£¬ÒºÌå¼ÓÈÈÒ×±©·Ð£¬¼ÓÈëËé´ÉƬ£¬ÒýÈëÆû»¯ÖÐÐÄ£¬·ÀÖ¹ÉÕÆ¿ÖеÄÒºÌ屩·Ð£»
(2)×¶ÐÎÆ¿ÖÐÓ¦¼ÓÈë±¥ºÍ̼ËáÄÆÈÜÒº £¬Æä×÷ÓÃÊÇÈܽâÒÒ´¼£¬·´Ó¦ÒÒËᣬ½µµÍÒÒËáÒÒõ¥Èܽâ¶È£¬±ãÓÚ»ìºÏÎïµÄ·ÖÀëÓëÌá´¿£»
(3)ÒÒËáÓëÒÒ´¼ÔÚŨÁòËá×÷ÓÃϼÓÈÈ·¢Éúõ¥»¯·´Ó¦Éú³ÉÒÒËáÒÒõ¥ºÍË®£¬Í¬Ê±¸Ã·´Ó¦¿ÉÄæ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCH3COOH+CH3CH2OH
CH3COOC2H5+H2O¡£