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(3)ÓûʹÍÓëÏõËá·´Ó¦Éú³ÉµÄÆøÌåÓëO2ºÍH2OÈ«²¿×ª»¯ÎªHNO3£¬ÖÁÉÙÒªO2 g
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Cu+4HNO3Ũ=Cu(NO3)2+NO2¡ü+2H2O 3Cu+8HNO3Ũ=3Cu(NO3)2+2NO¡ü+4H2O
x x 1.5y y
64(x+1.5y)= 44.8 g x+y=0.5mol x= 0.1mol y=0.4mol
NaOH---------HNO3--------0.5 Cu2+
10-3av 0.7mol n(N)= 10-3av +0.5