ÌâÄ¿ÄÚÈÝ
ºãκãÈÝÌõ¼þÏ£¬Áò¿ÉÒÔ·¢ÉúÈçÏÂת»¯£¬Æä·´Ó¦¹ý³ÌºÍÄÜÁ¿¹ØÏµÈçͼ1Ëùʾ¡££¨ÒÑÖª£º
2SO2(g)+O2(g)
2SO3(g) ¡÷H= £196£®6 KJ¡¤mol-1£©
2SO2(g)+O2(g)
Çë»Ø´ðÏÂÁÐÎÊÌâ
£¨1£©Ð´³öÄܱíʾÁòµÄȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º____________________________¡£
£¨2£©¦¤H2=_____________KJ¡¤mol-1
£¨3£©ºãκãÈÝʱ£¬1molSO2ºÍ2molO2³ä·Ö·´Ó¦£¬·Å³öÈÈÁ¿µÄÊýÖµ±È¨O¦¤H2 ¨O__________ (Ìî¡°´ó¡±¡°Ð¡¡±»ò¡°ÏàµÈ¡±)
£¨4£©½«¢óÖеĻìºÏÆøÌåͨÈë×ãÁ¿µÄNaOHÈÜÒºÖÐÏûºÄNaOHµÄÎïÖʵÄÁ¿Îª______________£¬ÈôÈÜÒºÖз¢ÉúÁËÑõ»¯»¹Ô·´Ó¦£¬Ôò¸Ã¹ý³ÌµÄÀë×Ó·½³ÌʽΪ______________________¡£
£¨5£©ºãÈÝÌõ¼þÏ£¬ÏÂÁдëÊ©ÖÐÄÜʹn(SO3)/ n(SO2 )Ôö´óµÄÓÐ_______________¡£
a£®Éý¸ßζȣ» b£®³äÈëHeÆø c£®ÔÙ³äÈë1molSO2(g)ºÍ1molO2 (g) d£®Ê¹Óô߻¯¼Á
£¨6£©Ä³SO2(g)ºÍO2(g)Ìåϵ£¬Ê±¼ät1´ïµ½Æ½ºâºó£¬¸Ä±äijһÍâ½çÌõ¼þ£¬·´Ó¦ËÙÂÊÓëʱ¼ätµÄ¹ØÏµÈçͼ2Ëùʾ£¬Èô²»¸Ä±äSO2(g)ºÍO2(g)µÄÁ¿£¬ÔòͼÖÐt4ʱÒýÆðƽºâÒÆ¶¯µÄÌõ¼þ¿ÉÄÜÊÇ__________________£»Í¼Öбíʾƽºâ»ìºÏÎïÖÐSO3µÄº¬Á¿×î¸ßµÄÒ»¶Îʱ¼äÊÇ________________________¡£
£¨1£©Ð´³öÄܱíʾÁòµÄȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º____________________________¡£
£¨2£©¦¤H2=_____________KJ¡¤mol-1
£¨3£©ºãκãÈÝʱ£¬1molSO2ºÍ2molO2³ä·Ö·´Ó¦£¬·Å³öÈÈÁ¿µÄÊýÖµ±È¨O¦¤H2 ¨O__________ (Ìî¡°´ó¡±¡°Ð¡¡±»ò¡°ÏàµÈ¡±)
£¨4£©½«¢óÖеĻìºÏÆøÌåͨÈë×ãÁ¿µÄNaOHÈÜÒºÖÐÏûºÄNaOHµÄÎïÖʵÄÁ¿Îª______________£¬ÈôÈÜÒºÖз¢ÉúÁËÑõ»¯»¹Ô·´Ó¦£¬Ôò¸Ã¹ý³ÌµÄÀë×Ó·½³ÌʽΪ______________________¡£
£¨5£©ºãÈÝÌõ¼þÏ£¬ÏÂÁдëÊ©ÖÐÄÜʹn(SO3)/ n(SO2 )Ôö´óµÄÓÐ_______________¡£
a£®Éý¸ßζȣ» b£®³äÈëHeÆø c£®ÔÙ³äÈë1molSO2(g)ºÍ1molO2 (g) d£®Ê¹Óô߻¯¼Á
£¨6£©Ä³SO2(g)ºÍO2(g)Ìåϵ£¬Ê±¼ät1´ïµ½Æ½ºâºó£¬¸Ä±äijһÍâ½çÌõ¼þ£¬·´Ó¦ËÙÂÊÓëʱ¼ätµÄ¹ØÏµÈçͼ2Ëùʾ£¬Èô²»¸Ä±äSO2(g)ºÍO2(g)µÄÁ¿£¬ÔòͼÖÐt4ʱÒýÆðƽºâÒÆ¶¯µÄÌõ¼þ¿ÉÄÜÊÇ__________________£»Í¼Öбíʾƽºâ»ìºÏÎïÖÐSO3µÄº¬Á¿×î¸ßµÄÒ»¶Îʱ¼äÊÇ________________________¡£
£¨1£©S(s)+O2(g)==SO2(g) ¦¤H=-297 KJ¡¤mol-1
£¨2£©-78.64
£¨3£©´ó
£¨4£©2mol£»2SO2+O2+4OH-==2SO42-+2H2O
£¨5£©C
£¨6£©Éý¸ßζȣ»t3¡«t4
£¨2£©-78.64
£¨3£©´ó
£¨4£©2mol£»2SO2+O2+4OH-==2SO42-+2H2O
£¨5£©C
£¨6£©Éý¸ßζȣ»t3¡«t4
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿