ÌâÄ¿ÄÚÈÝ

·Ûĩ״ÊÔÑùAÊÇÓɵÈÎïÖʵÄÁ¿µÄMgOºÍFe2O3×é³ÉµÄ»ìºÏÎï¡£½øÐÐÈçÏÂʵÑ飺

¢ÙÈ¡ÊÊÁ¿A½øÐÐÂÁÈÈ·´Ó¦£¬²úÎïÖÐÓе¥ÖÊBÉú³É£»

¢ÚÁíÈ¡20 g AÈ«²¿ÈÜÓÚ0.15 L 6.0 mol¡¤L-1ÑÎËáÖУ¬µÃÈÜÒºC£»

¢Û½«¢ÙÖеõ½µÄµ¥ÖÊBºÍÈÜÒºC·´Ó¦£¬·Å³ö1.12 L(±ê×¼×´¿ö)ÆøÌ壬ͬʱÉú³ÉÈÜÒºD£¬»¹²ÐÁôÓйÌÌåÎïÖÊB£»

¢ÜÓÃKSCNÈÜÒº¼ìÑéʱ£¬ÈÜÒºD²»±äÉ«¡£

ÇëÌî¿Õ£º

(1)¢ÙÖÐÒý·¢ÂÁÈÈ·´Ó¦µÄʵÑé²Ù×÷ÊÇ________________£¬²úÎïÖеĵ¥ÖÊBÊÇ_______________¡£

(2)¢ÚÖÐËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ________________________________________________¡£

(3)¢ÛÖÐËù·¢ÉúµÄ¸÷·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ____________________________________________¡£

(4)ÈôÈÜÒºDµÄÌå»ýÈÔÊÓΪ0.15 L£¬Ôò¸ÃÈÜÒºÖÐc(Mg2+)Ϊ___________£¬c(Fe2+)Ϊ___________¡£

(1)¼ÓÉÙÁ¿KClO3£¬²åÉÏþÌõ²¢½«Æäµãȼ  Fe

(2)Fe2O3+6HCl2FeCl3+3H2O¡¢MgO+2HClMgCl2+H2O

(3)Fe+2H+Fe2++H2¡ü¡¢Fe+2Fe3+3Fe2+

(4)0.67 mol¡¤L-1  2.33 mol¡¤L-1

½âÎö£º(4)ÉèMgOÓëFe2O3µÄÎïÖʵÄÁ¿Îªx£¬

¸ù¾ÝÌâÒâÓÐ:40x+160x=20£¬x=0.1 mol£¬

ÈÜÒºDÖÐÓÐMg2+ 0.1 mol¡£

Fe2O3¡«2Fe3+¡«3Fe2+

0.1 mol            0.3 mol

Fe+2H+Fe2+  +  H2¡ü

          0.05 mol  0.05 mol

ÈÜÒºDÖÐÓÐFe2+£º0.3 mol+0.05 mol=0.35 mol£¬

ÈÜÒºDÖÐc(Mg2+)==0.67 mol¡¤L-1£¬

c(Fe2+)==2.33 mol¡¤L-1¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø