ÌâÄ¿ÄÚÈÝ
Òò¡°ÕÙ»ØÃÅ¡±¶øÄֵ÷зÐÑïÑïµÄ·áÌïPriusÊôµÚÈý´ú»ìºÏ¶¯Á¦³µ£¬¿ÉÒÔÓõ綯»ú¡¢ÄÚȼ»ú»ò¶þÕß½áºÏÍÆ¶¯³µÂÖ¡£Æû³µÉÏÆÂ»ò¼ÓËÙʱ£¬µç¶¯»úÌá¹©ÍÆ¶¯Á¦£¬½µµÍÁËÆûÓ͵ÄÏûºÄ£»ÔÚɲ³µºÍÏÂÆÂʱµç¶¯»ú´¦ÓÚ³äµç״̬¡£
(1)»ìºÏ¶¯Á¦³µµÄÄÚȼ»úÒÔÆûÓÍΪȼÁÏ£¬ÆûÓÍ£¨ÒÔÐÁÍéC8H18¼Æ£©ºÍÑõÆø³ä·Ö·´Ó¦£¬Ã¿Éú³É1molË®ÕôÆø·Å ÈÈ569.1 kJ¡£Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ___________________
(2)»ìºÏ¶¯Á¦³µµÄµç¶¯»úĿǰһ°ãʹÓõÄÊÇÄøÇâµç³Ø£¬ ÄøÇâµç³Ø²ÉÓÃÄøµÄ»¯ºÏÎïΪÕý¼«£¬´¢Çâ½ðÊô£¨ÒÔM ±íʾ£©Îª¸º¼«£¬¼îÒº£¨Ö÷ҪΪKOH£©Îªµç½âÒº¡£
¢ÙÄøÇâµç³Ø³ä·ÅµçÔÀíÈçͼËùʾ£¨Í¼ÖÐMHΪÎü¸½ÁËÇâÔ×ӵĴ¢ÇâºÏ½ð£©£¬Æä×Ü·´Ó¦Ê½ÊÇ____________________¡£
(1)»ìºÏ¶¯Á¦³µµÄÄÚȼ»úÒÔÆûÓÍΪȼÁÏ£¬ÆûÓÍ£¨ÒÔÐÁÍéC8H18¼Æ£©ºÍÑõÆø³ä·Ö·´Ó¦£¬Ã¿Éú³É1molË®ÕôÆø·Å ÈÈ569.1 kJ¡£Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ___________________
(2)»ìºÏ¶¯Á¦³µµÄµç¶¯»úĿǰһ°ãʹÓõÄÊÇÄøÇâµç³Ø£¬ ÄøÇâµç³Ø²ÉÓÃÄøµÄ»¯ºÏÎïΪÕý¼«£¬´¢Çâ½ðÊô£¨ÒÔM ±íʾ£©Îª¸º¼«£¬¼îÒº£¨Ö÷ҪΪKOH£©Îªµç½âÒº¡£
¢ÙÄøÇâµç³Ø³ä·ÅµçÔÀíÈçͼËùʾ£¨Í¼ÖÐMHΪÎü¸½ÁËÇâÔ×ӵĴ¢ÇâºÏ½ð£©£¬Æä×Ü·´Ó¦Ê½ÊÇ____________________¡£
¢Ú¸ù¾ÝËù¸øÐÅÏ¢Åжϣ¬»ìºÏ¶¯Á¦³µÏÂÆÂ»òɲ³µÊ±£¬¼×µç¼«µÄµç¼«·´Ó¦Ê½Îª_________________£»»ìºÏ¶¯Á¦³µÉÏÆÂ»ò¼ÓËÙʱ£¬Òҵ缫µÄµç¼«·´Ó¦Ê½Îª____________________
(3)Æû³µÎ²ÆøÖеÄÒ»Ñõ»¯Ì¼ÊÇ´óÆøÎÛȾÎ¿Éͨ¹ýÈçÏ·´Ó¦½µµÍÆäŨ¶È£ºCO(g) +1/2O2(g)
CO2(g)
¢ÙijζÈÏ£¬ÔÚÁ½¸öÈÝÆ÷ÖнøÐÐÉÏÊö·´Ó¦£¬ÈÝÆ÷Öи÷ÎïÖÊµÄÆðʼŨ¶È¼°Õý¡¢Äæ·´Ó¦ËÙÂʹØÏµÈçϱíËù ʾ¡£ÇëÌîд±íÖеĿոñ¡£
¢ÚÏàͬζÈÏ£¬Ä³Æû³µÎ²ÆøÖÐCO¡¢CO2µÄŨ¶È·Ö±ðΪ1.0¡Á10-5mol/LºÍ1.0¡Á10-4mol/L¡£ÈôÔÚÆû³µµÄÅÅÆø¹ÜÉÏÔö¼ÓÒ»¸ö²¹È¼Æ÷£¬²»¶Ï²¹³äO2²¢Ê¹ÆäŨ¶È±£³ÖΪ1.0¡Á10-4mol/L£¬Ôò×îÖÕÎ²ÆøÖÐCOµÄŨ¶ÈΪ____mol/L¡£
(1)C8H18(l) +25/2O2(g)= 8CO2(g) +9H2O(g) ¡÷H=-5121.9 kJ/mol
(2)¢ÙMH+NiOOH
M+Ni(OH)2£»¢ÚM+H2O+e-=MH+OH-£»NiOOH+H2O+e-= Ni(OH)2+OH-
(3)¢Ùv(Õý)<v(Äæ)£»¢Ú1.1¡Á10-6
(2)¢ÙMH+NiOOH
(3)¢Ùv(Õý)<v(Äæ)£»¢Ú1.1¡Á10-6
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿