ÌâÄ¿ÄÚÈÝ

»¯Ñ§ÓëÉú»î¡¢Éú²úϢϢÏà¹Ø£¬ÓÃÀë×Ó·´Ó¦·½³Ìʽ½âÊÍÉú»îÖл¯Ñ§µÄÓ¦Óá£
(1)ÓÃÑÎËá³ýÈ¥ÌúÐ⣨Ö÷Òª³É·ÖΪFe2O3£©________________£»
(2) Óá°Ð¡ËÕ´òƬ¡±ÖÎÁÆÎ¸Ëᣨ(0.2%¡«0.4%µÄÑÎËá)¹ý¶à___________________£»
(3)ÓÐÈËÓÃÍÁ·¨ÖÎÁÆÎ¸Ëá¹ý¶à²¡£¬·½·¨ÊÇ£º½«¼¦µ°Æ¤Ï´¾»¡¢ºæ¸É¡¢Ä¥Ï¸·þÓ㻾Ý˵ÕâÖÖÁÆ·¨Ð§¹û»¹²»´í¡£ÆäÖеĻ¯Ñ§Ô­Àí·´Ó¦ÊÇ_____________________________________£»
(4)Èç¹û²¡ÈËͬʱ»¼ÓÐθÀ£Ññ£¬´Ëʱ×îºÃ·þÓá°Î¸ÊæÆ½¡±£¨Al(OH)3£©£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________¡£
(1)Fe2O+6H+£½2Fe3++3H2O
(2)HCO3£­£«H£«===CO2¡ü£«H2O
(3)Al(OH)3£«3H£«===Al3£«£«3H2O
(4)CaCO3£«2H£«===Ca2£«£«CO2¡ü£«H2O
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø