ÌâÄ¿ÄÚÈÝ

³£ÎÂÏ£¬ÓÃ0.1000 mol¡¤L£­1¡¡NaOHÈÜÒºµÎ¶¨20.00 mL¡¡0.1000 mol¡¤L£­1¡¡CH3COOHÈÜÒºËùµÃµÎ¶¨ÇúÏßÈçͼ£®ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

[¡¡¡¡]

A£®

µã¢ÙËùʾÈÜÒºÖУºc(CH3COO£­)£«c(OH£­)£½c(CH3COOH)£«c(H+)

B£®

µã¢ÚËùʾÈÜÒºÖУºc(Na+)£½c(CH3COOH)£«c(CH3COO£­)

C£®

µã¢ÛËùʾÈÜÒºÖУºc(Na+)£¾c(OH£­)£¾c(CH3COO£­)£¾c(H+)

D£®

µÎ¶¨¹ý³ÌÖпÉÄܳöÏÖ£ºc(CH3COOH)£¾c(CH3COO£­)£¾c(H+)£¾c(Na+)£¾c(OH£­)

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ʳ´×·ÖΪÄðÔì´×ºÍÅäÖÆ´×Á½ÖÖ¡£¹ú¼Ò±ê×¼¹æ¶¨ÄðÔìʳ´××ÜËẬÁ¿²»µÃµÍÓÚ3.5 g/100 mL¡£
(1)ijÑо¿Ð¡×éÀûÓõζ¨·ÖÎö·¨²â¶¨Ä³Æ·ÅÆÊ³´×Öд×ËáµÄº¬Á¿£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ__________¡£
a£®ÓÃNaOHÈÜÒºµÎ¶¨Ê±·´Ó¦µÄÀë×Ó·½³ÌʽΪH++OH-=H2O
b£®Ê³´×ÊÔÑùÐèÏ¡ÊÍÒ»¶¨±¶ÊýºóÔÙ½øÐеζ¨
c£®ÓÃNaOHÈÜÒºµÎ¶¨Ê³´×£¬¿ÉʹÓ÷Ó̪»ò¼×»ù³È×÷ָʾ¼Á
d£®Èô²âµÃ¸ÃÆ·ÅÆÊ³´×µÄÎïÖʵÄÁ¿Å¨¶ÈΪ0. 75 mol/L£¬Ôò¸Ãʳ´×µÄ×ÜËáÁ¿Îª4.5 g/100 mL¡£
(2)Ñо¿Ð¡×éµÄͬѧ×Ðϸ¹Û²ìÁË¸ÃÆ·ÅÆÊ³´×µÄ±êÇ©£¬·¢ÏÖÆäÖл¹º¬Óб½¼×ËáÄÆ×÷ΪʳƷÌí¼Ó¼Á£¬ËûÏëÓÃ×ÊÁÏ·¨ÑéÖ¤´×ËáÓëʳƷÌí¼Ó¼Á(±½¼×ËáÄÆC6H5COONa)²»»á·¢ÉúÀë×Ó»¥»»·´Ó¦£¬Ðè²éÕÒÔÚÒ»¶¨Î¶ÈϵĴ×ËáÓë±½¼×ËáµÄ____________£¨ÌîдÐòºÅ£©¡£
a£®pH b£®µçÀë¶È c£®µçÀë³£Êý d£®Èܽâ¶È
(3)³£ÎÂÏ£¬ÓÃ0.100 0 mol/L NaOHÈÜÒº·Ö±ðµÎ¶¨20. 00 mL 0£®100 0 mol/L HClÈÜÒººÍ20. 00 mL
0£®100 0 mol/L CH3COOHÈÜÒº£¬µÃµ½2ÌõµÎ¶¨ÇúÏߣ¬ÈçÏÂͼËùʾ¡£
¢ÙµÎ¶¨´×ËáÈÜÒºµÄÇúÏßÊÇ____£¨Ìî¡°¼×¡±»ò¡°ÒÒ¡±£©£»µÎ¶¨ÇúÏßÖÐa=____mL£»
¢ÚEµãpH>8µÄÔ­ÒòÓÃÀë×Ó·½³Ìʽ±íʾ£º________________¡£
(4)ÏÖÓû´ÖÂԲⶨһδ֪Ũ¶ÈµÄCH3COOHÈÜÒºµÄµçÀë¶È£¬Ó¦×öµÄʵÑéºÍËùÐèµÄÊÔ¼Á£¨ÊÔÖ½£©ÊÇ____¡£
a£®µç½â£¬NaOHÈÜÒº b£®ÕôÁó£¬Na2CO3ÈÜÒº c£®õ¥»¯·´Ó¦£¬Ê¯ÈïÊÔÒº d£®Öк͵樣¬pHÊÔÖ½

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø