题目内容

1gH2燃烧生成液态水放出142.9kJ的热量,下列热化学方程式书写正确的是
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A.2H2(g)+ O2(g) = 2H2O (1) H = -142.9 kJ·mol-1
B.2H2(g)+ O2(g) = 2H2O (1) H = -571.6 kJ·mol-1
C.2H2+O2=2H2O H = -571.6l kJ·mol-1
D.H2(g)+1/2O2(g) = H2O (1) H = +285.8 kJ·mol-1
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