ÌâÄ¿ÄÚÈÝ
½«0.2 mol¡¤L-1 CH3COOKÓë0.1 mol¡¤L-1ÑÎËáµÈÌå»ý»ìºÏºó£¬ÈÜÒºÖÐÏÂÁÐÁ£×ÓµÄÎïÖʵÄÁ¿Å¨¶ÈµÄ¹ØÏµÕýÈ·µÄÊÇ( )A.c(CH3COO-)=c(Cl-)=c(H+)£¾c(CH3COOH)
B.c(CH3COO-)=c(Cl-)£¾c(CH3COOH)=c(H+)
C.c(CH3COO-)=c(Cl-)£¾c(H+)£¾c(CH3COOH)
D.c(CH3COO-)£¾c(Cl-)£¾c(CH3COOH)£¾c(H+)
D
½âÎö£ºCH3COOKÓëHCl·´Ó¦ºóÉú³ÉµÈÎïÖʵÄÁ¿µÄKClºÍCH3COOH£¬Í¬Ê±Ê£ÓàµÈÎïÖʵÄÁ¿µÄCH3COOK£¬Ôò´ËÈÜÒºÖÐÓÐc(CH3COO-)£¾c(Cl-)£¬ÔòA¡¢B¡¢C¾ù²»ÕýÈ·£¬¼´Ö»ÓÐDÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A¡¢Ä³Î¶ÈÏÂ
| ||
| B¡¢³£ÎÂÏ£¬pH=aµÄһԪǿËáÈÜÒºVa LÓëpH=bµÄ¶þԪǿ¼îÈÜÒºVb L»ìºÏ£¬Èç¹ûVb£ºVa=10£¨14-a-b£©£¬Ôò»ìºÏÈÜÒºÒ»¶¨³ÊÖÐÐÔ | ||
| C¡¢Ä³ÑÎÄܹ»·¢ÉúË®½â·´Ó¦£¬½«Æä¼ÓÈëˮһ¶¨ÄÜ´Ù½øË®µÄµçÀë | ||
| D¡¢½«0.2 mol?L-1 HClOÈÜÒººÍ0.1 mol?L-1NaOHÈÜÒºµÈÌå»ý»ìºÏºó£¬ÈÜÒºÏÔ¼îÐÔ£¬Ôò´Ë¹ØÏµÊ½£ºc£¨HClO£©-c£¨ClO-£©=2c£¨OH-£©-2c£¨H+£©Ò»¶¨ÕýÈ· |