ÌâÄ¿ÄÚÈÝ

£¨14·Ö£©ÓÃ98%µÄŨH2SO4£¨¦Ñ=1.84g/cm3£©ÅäÖÆ240mL0.5mol/LµÄÏ¡H2SO4£¬Çë°´ÒªÇóÌî¿Õ£º

£¨1£©ËùÓÃŨH2SO4µÄÎïÖʵÄÁ¿Å¨¶ÈΪ              £¬ÅäÖÆÊ±ËùÐèŨÁòËáµÄÌå»ýΪ       mL¡££¨¾ù±£ÁôһλСÊý£©

£¨2£©ÊµÑéÖÐÐèÒªÓõ½µÄ¶¨Á¿ÒÇÆ÷ÓР                                           ¡£

£¨3£©ÈôʵÑéÖгöÏÖÏÂÁÐÏÖÏó¶ÔËùÅäÈÜÒºµÄŨ¶ÈÓÐʲôӰÏ죿£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©

¢ÙŨÁòËáÈܽâºóδÀäÖÁÊÒμ´½øÐÐ×ªÒÆ¡¢¶¨ÈÝ¡££¨                  £©

¢Ú¶¨ÈÝʱ¸©Êӿ̶ÈÏß¡££¨                   £©

£¨4£©Èô¶¨ÈÝÊ±ÒºÃæ¸ßÓڿ̶ÈÏßÓ¦²ÉÈ¡µÄ´ëÊ©ÊÇ                ¡£

£¨5£©ÈôʵÑé²Ù×÷È«²¿ÎÞÎó£¬×îºóËùµÃµÄÈÜÒºÓ¦´æ·ÅÔÚÊÔ¼ÁÆ¿ÖУ¬²¢ÌùÉϱêÇ©£¬ÇëÄã°ïÖú°Ñ±êÇ©ÉϵÄÄÚÈÝдһÏ£¨ÈçÓÒͼ£©¡£

 

¡¾´ð°¸¡¿

 

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÖÓÃ98%µÄŨH2SO4£¨ÃܶÈΪ1.84g/cm3£©À´ÅäÖÆ500mL0.2mol/LµÄÏ¡H2SO4£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¾­¼ÆË㣬ÐèŨH2SO4µÄÌå»ýΪ
5.4
5.4
mL£®£¨±£ÁôһλСÊý£©
£¨2£©ÏÖ¸ø³öÏÂÁÐÒÇÆ÷£¨ÅäÖÆ¹ý³ÌÖпÉÄÜÓõ½£©£º¢Ù100mLÁ¿Í² ¢Ú10mLÁ¿Í² ¢Û250mLÉÕ±­  ¢ÜÍÐÅÌÌìÆ½ ¢Ý500mLÈÝÁ¿Æ¿ ¢Þ½ºÍ·µÎ¹Ü ¢ß²£Á§°ô
°´ÕýÈ·²Ù×÷±ØÐèʹÓÃÒÇÆ÷µÄÏȺó˳ÐòÅÅÁÐÕýÈ·µÄÊÇ
D
D

A£®¢Ü¢Û¢ß¢Ý¢ÞB£®¢Ú¢Ý¢ß¢ÞC£®¢Ù¢Û¢Ý¢Þ¢ßD£®¢Ú¢Þ¢Û¢ß¢Ý¢Þ
£¨3£©Ð´³öŨÁòËáÏ¡ÊͲÙ×÷µÄÒªµã
½«Å¨ÁòËáÑØÉÕ±­±ÚÂýÂý¼ÓÈë×°ÓÐË®µÄÉÕ±­ÖУ¬²¢Óò£Á§°ô½Á°è£®
½«Å¨ÁòËáÑØÉÕ±­±ÚÂýÂý¼ÓÈë×°ÓÐË®µÄÉÕ±­ÖУ¬²¢Óò£Á§°ô½Á°è£®

£¨4£©¶ÔËùÅäÖÆµÄÏ¡H2SO4½øÐвⶨ£¬·¢ÏÖŨ¶È´óÓÚ0.2mol/L£®ÇëÄã·ÖÎöÏÂÁÐÄÄЩ²Ù×÷»áÒýÆðËùÅäŨ¶ÈÆ«´ó£¨Ìîд×Öĸ£©
ACF
ACF
£®
A£®ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱ£¬ÑöÊÓÁ¿Í²µÄ¿Ì¶È
B£®ÈÝÁ¿Æ¿Î´¸ÉÔï¼´ÓÃÀ´ÅäÖÆÈÜÒº
C£®Å¨ÁòËáÔÚÉÕ±­ÖÐÏ¡Êͺó£¬Î´ÀäÈ´¾ÍÁ¢¼´×ªÒƵ½ÈÝÁ¿Æ¿ÖУ¬²¢½øÐж¨ÈÝ£»
D£®ÍùÈÝÁ¿Æ¿×ªÒÆÊ±£¬ÓÐÉÙÁ¿ÒºÌ彦³ö
E£®ÉÕ±­Î´½øÐÐÏ´µÓ
F£®ÔÚÈÝÁ¿Æ¿Öж¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏß
G£®¶¨ÈݺóÈûÉÏÆ¿Èû·´¸´Ò¡ÔÈ£¬¾²Öúó£¬ÒºÃæ²»µ½¿Ì¶ÈÏߣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏߣ®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø