ÌâÄ¿ÄÚÈÝ

£¨1£©ÖкÍÈȲⶨµÄʵÑéÖУ¬Óõ½µÄ²£Á§ÒÇÆ÷ÓÐÉÕ±­¡¢Î¶ȼơ¢Á¿Í²¡¢______£®
£¨2£©Á¿È¡·´Ó¦Îïʱ£¬È¡50mL 0.50mol?L-1µÄÑÎËᣬ»¹Ðè¼ÓÈëµÄÊÔ¼ÁÊÇ______£¨ÌîÐòºÅ£©£®
A£®50mL 0.50mol?L-1 NaOHÈÜÒº
B£®50mL 0.55mol?L-1 NaOHÈÜÒº
C£®1.0g NaOH¹ÌÌå
£¨3£©ÒÑ֪ϡÑÎËáÓëÏ¡ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÖкÍÈÈ¡÷H=-57.3kJ?mol-1£¬ÇëÓÃÀë×Ó·½³Ìʽ±íʾ¸ÃÖкͷ´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ______£®
£¨1£©ÖкÍÈȵIJⶨʵÑéÓõ½µÄ²£Á§ÒÇÆ÷ÓУºÉÕ±­¡¢Î¶ȼơ¢Á¿Í²¡¢½Á°èÆ÷£¬¹Ê´ð°¸Îª£º½Á°èÆ÷£»
£¨2£©ÎªÁ˱£Ö¤Ëá»òÊǼîÖеÄÒ»·½ÍêÈ«·´Ó¦£¬ÍùÍù±£Ö¤Ò»·½¹ýÁ¿£¬ËùÒÔ¿ÉÒÔÑ¡Ôñ50mL 0.55mol?L-1 NaOHÈÜÒº£¬¹Ê´ð°¸Îª£ºB£»
£¨3£©Ï¡ÑÎËáÓëÏ¡ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÖкÍÈÈÈÈ»¯Ñ§·´Ó¦·½³ÌʽΪ£ºH+£¨aq£©+OH-£¨aq£©=H2O£¨aq£©£¬¡÷H=-57.3kJ?mol-1£¬
¹Ê´ð°¸Îª£ºH+£¨aq£©+OH-£¨aq£©=H2O£¨aq£©£¬¡÷H=-57.3kJ?mol-1£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø