ÌâÄ¿ÄÚÈÝ
£¨24·Ö£©ÏÂͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬Õë¶Ô±íÖеĢ١«¢âÖÐÔªËØ£¬ÌîдÏÂÁпոñ£º
|
|
|
| |||||||||||||||
|
|
|
|
| ¢Ù | ¢â | ¢Ú | ¢Û |
| |||||||||
|
| ¢Ü | ¢Ý |
|
| ¢ß | ¢à | ¢á | ||||||||||
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| ¢Þ |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
¢ÅÔÚÕâ10ÖÖÔªËØÖУ¬Ô×Ó°ë¾¶½ÏСµÄÊÇ________(ÌîÔªËØ·ûºÅ)£¬»¯Ñ§ÐÔÖÊ×î²»»îÆÃµÄÔªËØÊÇ_____(Ìî¡°ÔªËØ·ûºÅ¡±)£»ÆäÖÐÒ»ÖÖºËËØ¿É²â¶¨ÎÄÎïÄê´ú£¬ÕâÖÖºËËØµÄ·ûºÅÊÇ ¡£
¢ÆÔªËآٵÄÔ×ӽṹʾÒâͼΪ__________£»ÔªËآٵÄ×î¸ß¼ÛÑõ»¯Îï½á¹¹Ê½Îª£º________£¬ÔªËØ¢âµÄµ¥Öʵç×ÓʽΪ£º__________¡£
ÇëÓõç×Óʽ±íʾ»¯ºÏÎï¢ÜºÍ¢àµÄÐγɹý³Ì
________________________________________________¡£
¢ÇÔªËØ¢ÝµÄÑõ»¯ÎïÓëÑÎËá·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º _________________________________¡£
ÔªËØ¢ÝµÄµ¥ÖÊÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º ________________________________¡£
¢ÈÔªËØ¢ÝµÄµ¥ÖÊÓëFeºÍÏ¡ÁòËá¹¹³ÉÔµç³Ø£¬ÊÔÔÚÏÂÃæµÄ·½¿òÄÚ»³öÔµç³Ø×°ÖÃͼ£¬±ê³öÔµç³ØµÄµç¼«²ÄÁϺ͵ç½âÖÊÈÜÒº£¬²¢Ð´³ö¸º¼«µÄµç¼«·´Ó¦Îª___________________________¡£
£¨5£©ÔªËآ൥ÖÊÄÜÈÜÓÚË®£¬Ë®Òº³Ê É«£¬ÔÚÆäÖÐͨÈëÔªËØ¢ßµÄijÖÖÑõ»¯ÎÈÜÒºÑÕÉ«ÍÊÈ¥£¬Óû¯Ñ§·½³Ìʽ±íʾÔÒò ¡£
£¨6£©ÔªËآߵÄ×î¸ßÕý¼ÛºÍ×îµÍ¸º¼Û·Ö±ðΪ ¡¢ ¡¡ ¡¡£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬ÔªËØ¢ßÓëH2·´Ó¦ÓÐÒ»¶¨ÏÞ¶È(¿ÉÀí½âΪ·´Ó¦½øÐеij̶È)£¬ÇëÅжÏÔÚÏàͬÌõ¼þÏÂÔªËØ¢ÞÓëH2·´Ó¦µÄÏÞ¶È(Ñ¡Ìî¡°¸ü´ó¡±¡¢¡°¸üС¡±»ò¡°Ïàͬ¡±) ¡¡¡¡¡¡ ¡£
£¨24·Ö£©
(1)F, Ar £¬14C £¨3·Ö£©£¬ (2) £»O=C=O£»
£¨3·Ö£©£¬
£¨2·Ö£©£¬
(3) Al2O3 + 6H+=2Al3+ +3H2O£»2Al +2NaOH+2H2O=2NaAlO2+3H2¡ü£¨4·Ö£©
(4)
Al£3e£ £½Al3£«£¨2·Ö£©£¨2·Ö£©£¬
(5)dz»ÆÂÌÉ«£¬SO2 + Cl2 + 2 H2O = H2SO4+ 2 H Cl £¨2·Ö£©
(6) +6£¨1·Ö£©£» -2 £¨1·Ö£© £» ¸üС£¨1·Ö£©
½âÎö: