ÌâÄ¿ÄÚÈÝ

(8·Ö)ijѧÉúÀûÓÃÒÔÏÂ×°ÖÃ̽¾¿ÂÈÆøÓë°±ÆøÖ®¼äµÄ·´Ó¦¡£ÆäÖÐA¡¢F·Ö±ðΪ°±ÆøºÍÂÈÆøµÄ·¢Éú×°Öã¬CΪ´¿¾»¸ÉÔïµÄÂÈÆøÓë°±Æø·´Ó¦µÄ×°Öá£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)×°ÖÃFÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________¡££¨Ìáʾ£¬¸ßÃÌËá¼ØµÄ»¹Ô­²úÎïΪMn2+£©
(2) B×°ÖõÄÃû³ÆÊÇ__________£»A×°ÖÃÖеĹÌÌå¿ÉÄÜÊÇ________¡£
(3)ͨÈëC×°ÖõÄÁ½¸ùµ¼¹Ü×ó±ß½Ï³¤¡¢Óұ߽϶̣¬Ä¿µÄÊÇ__________________¡£
(4)×°ÖÃCÄÚ³öÏÖŨºñµÄ°×Ñ̲¢ÔÚÈÝÆ÷ÄÚ±ÚÄý½á£¬ÁíÒ»Éú³ÉÎïÊÇ¿ÕÆøµÄÖ÷Òª³É·ÖÖ®Ò»¡£Çëд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________________________

£¨1£©2MnO4- + 10 Cl- + 16H+ = Mn2+ + 5Cl2¡ü + 8H2O           £¨2·Ö£©
(2) ¸ÉÔï¹Ü£¨1·Ö£©¡¡            ¼îʯ»Ò»òÉúʯ»ÒµÈ     £¨1·Ö£©
(3) ʹÃܶȴóµÄÂÈÆøÓëÃܶÈСµÄ°±Æø½Ï¿ìµØ¾ùÔÈ»ìºÏ          £¨2·Ö£©
(4) 3Cl2£«8NH3===N2£«6NH4Cl¡¡                           £¨2·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø