ÌâÄ¿ÄÚÈÝ

ÒÑ֪ijζÈʱCH3COOHµÄµçÀëÆ½ºâ³£ÊýΪK£®¸ÃζÈÏÂÏò20mL0.1mol/LCH3COOHÈÜÒºÖÐÖðµÎ¼ÓÈë0.1mol/L NaOHÈÜÒº£¬ÆäpH±ä»¯ÇúÏßÈçͼËùʾ£¨ºöÂÔζȱ仯£©£®ÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
·ÖÎö£ºA£®aµãpH=3£¬ÓÉCH3COOH¨TCH3COO-+H+·ÖÎö£»
B£®bµãÈÜÒºÏÔËáÐÔ£¬ÓɵçºÉÊØºã·ÖÎö£»
C£®cµãÈÜÒºµÄpH=7£»
D£®b¡¢d µãζȲ»±ä£¬ÔòK²»±ä£®
½â´ð£º½â£ºA£®aµãpH=3£¬ÓÉCH3COOH¨TCH3COO-+H+¿ÉÖª£¬c£¨H+£©=c£¨CH3COO-£©=10-3mol/L£¬¹ÊAÕýÈ·£»
B£®bµãÈÜÒºÏÔËáÐÔ£¬c£¨H+£©£¾c£¨OH-£©£¬ÓɵçºÉÊØºã¿ÉÖª£¬c£¨Na+£©£¼c£¨CH3COO-£©£¬¹ÊB´íÎó£»
C£®cµãÈÜÒºµÄpH=7£¬ÈôCH3COOHºÍNaOHÇ¡ºÃ·´Ó¦ÍêÈ«Éú³É´×ËáÄÆ£¬ÈÜÒºµÄpH£¾7£¬Ó¦´×ËáÊ£Ó࣬¹ÊC´íÎó£»
D.
c(CH3COO-)?c(H+)
c(CH3COOH)
=Ka£¬b¡¢d µãζȲ»±ä£¬ÔòK²»±ä£¬¹ÊDÕýÈ·£»
¹ÊÑ¡BC£®
µãÆÀ£º±¾Ì⿼²éËá¼î»ìºÏÈÜÒºµÄ¶¨ÐÔÅжϣ¬Ã÷ȷͼÏóÖи÷µãµÄpH¼°ÈÜÒºÖеÄÈÜÖʼ´¿É½â´ð£¬×¢ÒâµçºÉÊØºã¼°µçÀëÆ½ºâ³£ÊýÖ»ÓëζÈÓйأ¬ÌâÄ¿ÄѶȲ»´ó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø