ÌâÄ¿ÄÚÈÝ


ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ(¡¡¡¡)

A£®ÂÁƬÓëNaOHÈÜÒº·´Ó¦£ºAl£«2OH£­===AlO£«H2¡ü

B£®Ï¡ÏõËáÖмÓÈëÉÙÁ¿Ì¼ËáÑÇÌú£ºFeCO3£«2H£«===Fe2£«£«CO2¡ü£«H2O

C£®±¥ºÍ̼ËáÄÆÈÜÒºÖÐͨÈë¶þÑõ»¯Ì¼ÆøÌ壺2Na£«£«CO£«CO2£«H2O===2NaHCO3¡ý

D£®Ba(OH)2Óë¹ýÁ¿µÄNH4HSO4·´Ó¦£ºBa2£«£«2OH£­£«2H£«£«SO===BaSO4¡ý£«2H2O


½âÎö£ºAÏîµçºÉ²»Êغ㣬ӦΪ2Al£«2OH£­£«2H2O===2AlO£«3H2¡ü£»BÏîºöÂÔHNO3¶ÔFe2£«µÄÑõ»¯¡£

´ð°¸£ºCD


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ʵÑéÊÒ´Óº¬µâ·ÏÒº(³ýH2OÍ⣬º¬ÓÐCCl4¡¢I2¡¢I£­µÈ)ÖлØÊյ⣬ÆäʵÑé¹ý³ÌÈçÏ£º

(1)Ïòº¬µâ·ÏÒºÖмÓÈëÉÔ¹ýÁ¿µÄNa2SO3ÈÜÒº£¬½«·ÏÒºÖеÄI2»¹Ô­ÎªI£­£¬ÆäÀë×Ó·½³ÌʽΪ__________________£»¸Ã²Ù×÷½«I2»¹Ô­ÎªI£­µÄÄ¿µÄÊÇ______________________¡£

(2)²Ù×÷XµÄÃû³ÆÎª________¡£

(3)Ñõ»¯Ê±£¬ÔÚÈý¾±ÉÕÆ¿Öн«º¬I£­µÄË®ÈÜÒºÓÃÑÎËáµ÷ÖÁpHԼΪ2£¬»ºÂýͨÈëCl2£¬ÔÚ40 ¡æ×óÓÒ·´Ó¦(ʵÑé×°ÖÃÈçͼËùʾ)¡£

ʵÑé¿ØÖÆÔڽϵÍζÈϽøÐеÄÔ­ÒòÊÇ______________£»×¶ÐÎÆ¿ÀïÊ¢·ÅµÄÈÜҺΪ________¡£

(4)ÒÑÖª£º5SO£«2IO£«2H£«===I2£«5SO£«H2O

ijº¬µâ·ÏË®(pHԼΪ8)ÖÐÒ»¶¨´æÔÚI2£¬¿ÉÄÜ´æÔÚI£­¡¢IOÖеÄÒ»ÖÖ»òÁ½ÖÖ¡£Çë²¹³äÍêÕû¼ìÑ麬µâ·ÏË®ÖÐÊÇ·ñº¬ÓÐI£­¡¢IOµÄʵÑé·½°¸£ºÈ¡ÊÊÁ¿º¬µâ·ÏË®ÓÃCCl4¶à´ÎÝÍÈ¡¡¢·ÖÒº£¬Ö±µ½Ë®²ãÓõí·ÛÈÜÒº¼ìÑé²»³öÓеⵥÖÊ´æÔÚ£»________________________________________________________________________

________________________________________________________________________

________________________________________________________________________¡£

ʵÑéÖпɹ©Ñ¡ÔñµÄÊÔ¼Á£ºÏ¡ÑÎËá¡¢µí·ÛÈÜÒº¡¢FeCl3ÈÜÒº¡¢Na2SO3ÈÜÒº¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø