ÌâÄ¿ÄÚÈÝ

ÏÖ´ú¼ÒÍ¥×°ÐÞÖÐÔ¡ÊÒ´ó¶àÓÃÈ¼ÆøÈÈË®Æ÷ÌṩÈÈË®£¬Èç¹ûijͬѧϴһ´ÎÔèÓÃÈÈË®50kg£®ÒÑ֪ˮ½øÈëÈÈË®Æ÷ǰµÄζÈÊÇ10¡æ£¬Ï´ÔèʱÈÈË®Æ÷Êä³öÈÈË®µÄζÈÉ趨Ϊ40¡æ£¨ÒÑÖª£ºÌìÈ»ÆøµÄÈÈÖµq=4.0¡Á107J£¯m3£¬ÆøÌåÍêȫȼÉշųöµÄÈÈÁ¿µÄ¹«Ê½Q=qV£¬Ê½ÖÐV±íʾȼÉÕÆøÌåµÄÌå»ý)¡£Ë®µÄ±ÈÈÈÈÝΪ4.2¡Á103J/£¨Kg¡¤¡æ£©Çó£º

  (1)Ë®´ÓÈÈË®Æ÷ÖÐÎüÊÕµÄÈÈÁ¿£»

  (2)ÈôÌìÈ»ÆøÍêȫȼÉÕÊÍ·ÅÈÈÁ¿µÄ70£¥±»Ë®ÎüÊÕ£¬ÐèÒªÏûºÄ¶àÉÙm3µÄÌìÈ»Æø?

£¨1£©QÎü=cm¡÷t=4.2¡Á103J/£¨kg¡¤¡æ£©¡Á50kg¡Á30¡æ=6.3¡Á106J                  £¨2·Ö£©

  £¨2£©¦Ç=£¨QÓÐ/Q×Ü£©¡Á100%   Q×Ü=QÓÐ/¦Ç=6.3¡Á106J/0.7=9.0¡Á106J             £¨2·Ö£©

Q=qV   V=Q/q=9.0¡Á106J/4.0¡Á107J£¯m3=0.225 m3                     £¨1·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø