Question

孝感城区每天清晨都要进行洒水，若一辆洒水车空车质量6t，水罐容积5m³.装满水后，车轮与地面的总接触面积为0.5m².（ g 取10N/kg，ρ_水=1.0×10³kg/m³）。

问：

（1）该车最多能装水的质量为多少？

（2）洒完一半水时，洒水车对地面的压强为多少？

（3）若罐内水深1.5m，则水对罐底的压强为多少？

Answer 1

（1）m=ρ_水V=1.0×10³kg/m³×5 m³=5×10³kg··························································· (1分)

（2）F=G_车+G_水=（6×10³+2.5×10³）kg×10N/kg=8.5×10⁴N····························· (1分)

P=F/S=8.5×10⁴N/0.5m²=1.7×10⁵Pa························································· (1分)

（3）P=ρ_水gh=1.0×10³kg/m³×10N/kg×1.5m=1.5×10⁴Pa···································· (1分)