ÌâÄ¿ÄÚÈÝ
ΪÁË̽¾¿¡°ÔÚµ¯ÐÔÏÞ¶ÈÄÚ£¬µ¯»ÉµÄÉ쳤ÓëÊܵ½µÄÀÁ¦µÄ¹ØÏµ¡±£¬ËùÓÃµÄÆ÷²ÄÊÇ£ºÒ»¸öÌú¼Ų̈¡¢Ò»¸ùÒ»¶ËÓл·Ò»¶ËÓй³µÄµ¯»É £¨ÄܳÐÊܵÄ×î´óÀÁ¦ÊÇ4N £©¡¢ÖØÁ¦ÊÇ0.5 N µÄ¹³ÂëÈô¸É£®
(1) ¸ÃʵÑ黹ÐèÒªµÄÆ÷²ÄÊÇ£º_________________________ £®
(2) ¼Ç¼µÄʵÑéÊý¾Ý¼ûÏÂ±í£®¸ù¾Ý±íÖеÄʵÑéÊý¾Ý£¬ÔÚͼ¼×µÄ ·½¸ñÖ½ÉÏ»³öµ¯»ÉµÄÉ쳤¡÷L ÓëÀÁ¦F µÄ¹ØÏµÍ¼Ïñ£¬ µ¯»ÉÔ³¤L0 =2.00 cm
(3) ¸ù¾ÝͼÏñ£¬¿ÉµÃ³öµÄ̽¾¿½áÂÛÊÇ£ºÔÚµ¯ÐÔÏÞ¶ÈÄÚ£¬______________________ £®
(4) ͼÒÒÊǸÃʵÑéËùÓõĵ¯»É£¬Èç¹ûÓÃÕâ¸ùµ¯»É×ÔÖÆµ¯»É²âÁ¦¼Æ£¬Ôò²âÁ¦¼ÆµÄÖ¸ÕëÓ¦°²×°ÔÚ__________µã£¬
(1) ¸ÃʵÑ黹ÐèÒªµÄÆ÷²ÄÊÇ£º_________________________ £®
(2) ¼Ç¼µÄʵÑéÊý¾Ý¼ûÏÂ±í£®¸ù¾Ý±íÖеÄʵÑéÊý¾Ý£¬ÔÚͼ¼×µÄ ·½¸ñÖ½ÉÏ»³öµ¯»ÉµÄÉ쳤¡÷L ÓëÀÁ¦F µÄ¹ØÏµÍ¼Ïñ£¬ µ¯»ÉÔ³¤L0 =2.00 cm
(3) ¸ù¾ÝͼÏñ£¬¿ÉµÃ³öµÄ̽¾¿½áÂÛÊÇ£ºÔÚµ¯ÐÔÏÞ¶ÈÄÚ£¬______________________ £®
(4) ͼÒÒÊǸÃʵÑéËùÓõĵ¯»É£¬Èç¹ûÓÃÕâ¸ùµ¯»É×ÔÖÆµ¯»É²âÁ¦¼Æ£¬Ôò²âÁ¦¼ÆµÄÖ¸ÕëÓ¦°²×°ÔÚ__________µã£¬
(1)¿Ì¶È³ß
(2)
(3)µ¯»ÉµÄÉ쳤ÓëÊܵ½µÄÀÁ¦³ÉÕý±È
(4)b
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿