Question

假设钢瓶内储满9千克液化气，钢瓶容积为0.3m³，今用去一半，则钢瓶内剩下的液化气密度为多少？

Answer 1

剩余气体密度ρ=

m1

V

=

m 2

V

=

m

2V

=

9kg

2×0.3m3

=15kg/m3．
答：剩余液化气密度为15kg/m³．