ÌâÄ¿ÄÚÈÝ
´òÀ̳Á´¬Ê±£¬³£ÏȽ«½ðÊô¸¡Ïä×¢ÂúË®£¬³ÁÈëË®µ×£¬ÔÙÓøÖÉþ½«Æä¹Ì¶¨ÔÚ³Á´¬ÉÏ£¬È»ºóÏò¸¡ÏäÖÐѹÈëÆøÌ壬Åųö¸¡ÏäÄÚµÄË®£¬ÕâÑù¸¡Ïä¾Í¿ÉÉϸ¡°Ñ³Á´¬ÀÆð¡£Ä³´Î´òÀÌ×÷ÒµÖУ¬ËùÓõĸ¡Ïä±ß³¤Îª2mµÄÕý·½Ì壬×ÔÖØ2000N¡£µ±¸¡ÏäÉϱíÃæ³Áµ½¾àË®Ãæ20m´¦Ê±¡£Çó(g=l0N£¯kg)£º
(1)¡¢¸¡ÏäÉϱíÃæÊܵ½Ë®µÄѹǿ£»
(2)¡¢¸¡ÏäÊܵ½Ë®µÄ¸¡Á¦£»
(3)¡¢µ±°Ñ¸¡ÏäÄÚˮȫ²¿Åųö£¬¸¡ÏäÓë³Á´¬Ò»ÆðÔÈËÙÉϸ¡Ê±£¬¸¡Ïä¶Ô³Á´¬µÄÀÁ¦£»
(4)¡¢µ±¸¡ÏäÉϱíÃæ¸¡µ½ÓëË®ÃæÏàÆ½Ê±£¬´Ë¹ý³ÌÖи¡Á¦¶Ô¸¡Ïä×öµÄ¹¦¡£
(1)¸¡ÏäÉϱíÃæÊܵ½Ë®µÄѹǿ
p=
Ë®gh=1.0¡Á103kg£¯m3¡Ál0N£¯kg¡Á20m=2¡Á105Pa
(2)¸¡ÏäÊܵ½µÄ¸¡Á¦
=
ˮg
=1.0¡Á103kg£¯m3¡Ál0N£¯kg¡Á23m3=8¡Á104N
(3)¸¡Ïä¶Ô³Á´¬µÄÀÁ¦
=
Ò»G=8¡Á104NÒ»2¡Á103N=7.8¡Á103N
(4)¸¡Á¦¶Ô¸¡Ïä×öµÄ¹¦W=
h=8¡Á104 N¡Á20m=1.6¡Á106J
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿