题目内容
化简求值:[(x+2y)2﹣(x+y)(3x﹣y)﹣5y2]÷2x,其中x=﹣2,y=
.
解:[(x+2y)2﹣(x+y)(3x﹣y)﹣5y2]÷2x
=(x2+4xy+4y2﹣3x2﹣2xy+y2﹣5y2)÷2x
=(﹣2x2+2xy)÷2x
=y﹣x;
当x=﹣2,y=
时,原式=
﹣(﹣2)=
.
=(x2+4xy+4y2﹣3x2﹣2xy+y2﹣5y2)÷2x
=(﹣2x2+2xy)÷2x
=y﹣x;
当x=﹣2,y=
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