题目内容
计算:
(1)-9+5×(-6)-(-4)2÷(-8);
(2)100+16÷(-2)4-
-|-100|;
(3)-6÷[2
×(-1
)].
(1)-9+5×(-6)-(-4)2÷(-8);
(2)100+16÷(-2)4-
| 1 |
| 5 |
(3)-6÷[2
| 1 |
| 3 |
| 2 |
| 7 |
分析:(1)先算乘方,再算乘除,最后算加减;
(2)先算乘方和绝对值,再算除法,最后算加减;
(3)先算括号里面的,把带分数化为假分数计算,再算除法.
(2)先算乘方和绝对值,再算除法,最后算加减;
(3)先算括号里面的,把带分数化为假分数计算,再算除法.
解答:解:(1)原式=-9-30-16÷(-8)
=-3-30+2
=-31;
(2)原式=100+16÷16-
-100
=1-
=
;
(3)原式=-6÷(-
×
)
=-6÷(-3)
=2.
=-3-30+2
=-31;
(2)原式=100+16÷16-
| 1 |
| 5 |
=1-
| 1 |
| 5 |
=
| 4 |
| 5 |
(3)原式=-6÷(-
| 7 |
| 3 |
| 9 |
| 7 |
=-6÷(-3)
=2.
点评:此题考查有理数的混合运算,关键是搞清运算的顺序,判定计算结果的符号.
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