题目内容
计算:
(1)(-2)+3+1+(-3)+2+(-4);
(2)
+
+(-
);
(3)(-4
+(-3
)+6
+(-2
);
(4)(+1)+(-2)+(+3)+(-4)+…+(+99)+(-100).
(1)(-2)+3+1+(-3)+2+(-4);
(2)
| 2 |
| 5 |
| 2 |
| 11 |
| 2 |
| 5 |
(3)(-4
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
(4)(+1)+(-2)+(+3)+(-4)+…+(+99)+(-100).
分析:(1)首先去括号,然后利用有理数的加减运算法则求解即可求得答案;注意互为相反数的和为0;
(2)首先去括号,然后利用有理数的加减运算法则求解即可求得答案;注意互为相反数的和为0;
(3)首先去括号,然后利用有理数的加减运算法则求解即可求得答案;注意同分母分数先相加减;
(4)首先原式可变形为:(1-2)+(3-4)+(5-6)+…+(99-100),继而可求得答案.
(2)首先去括号,然后利用有理数的加减运算法则求解即可求得答案;注意互为相反数的和为0;
(3)首先去括号,然后利用有理数的加减运算法则求解即可求得答案;注意同分母分数先相加减;
(4)首先原式可变形为:(1-2)+(3-4)+(5-6)+…+(99-100),继而可求得答案.
解答:解:(1)(-2)+3+1+(-3)+2+(-4)=-2+3+1-3+2-4=1-4=-3;
(2)
+
+(-
)=
-
+
=
;
(3)(-4
)+(-3
)+6
+(-2
)=-4
-3
+6
-2
=6
-10
=-3
;
(4)(+1)+(-2)+(+3)+(-4)+…+(+99)+(-100)=(1-2)+(3-4)+(5-6)+…+(99-100)=-1-1-1-…-1=-50.
(2)
| 2 |
| 5 |
| 2 |
| 11 |
| 2 |
| 5 |
| 2 |
| 5 |
| 2 |
| 5 |
| 2 |
| 11 |
| 2 |
| 11 |
(3)(-4
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 3 |
| 4 |
(4)(+1)+(-2)+(+3)+(-4)+…+(+99)+(-100)=(1-2)+(3-4)+(5-6)+…+(99-100)=-1-1-1-…-1=-50.
点评:此题考查了有理数的加减混合运算.此题比较简单,注意掌握符号的变化是解此题的关键.
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