题目内容
先化简,再求值:(| 2x |
| x2-4 |
| 1 |
| x-2 |
| x |
| x-2 |
| 1 |
| 2009 |
分析:先通分计算括号里的减法,再把除法转化成乘法进行计算,最后把x的值代入计算即可.
解答:解:(
-
)÷
=[
-
]•
=[
]•
=
,
把x=
代入上式,
=
=-
.
| 2x |
| x2-4 |
| 1 |
| x-2 |
| x |
| x-2 |
=[
| 2x |
| (x+2)(x-2) |
| x+2 |
| (x+2)(x-2) |
| x-2 |
| x |
=[
| x-2 |
| (x+2)(x-2) |
| x-2 |
| x |
=
| x-2 |
| x(x+2) |
把x=
| 1 |
| 2009 |
| x-2 |
| x(x+2) |
| ||||
|
| 8070153 |
| 4019 |
点评:本题考查了分式的化简求值.解题的关键是对分式通分,对分式的分子、分母要进行因式分解,约分化简.
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