题目内容
先化简,再求值:
÷(x+2-
),其中x=
-3.
| x-3 |
| x-2 |
| 5 |
| x-2 |
| 5 |
分析:先算括号内的减法,再把除法变成乘法,约分后代入求出即可.
解答:解:
÷(x+2-
)
=
÷
=
÷
=
•
=
,
当x=
-3时,
原式=
=
=
.
| x-3 |
| x-2 |
| 5 |
| x-2 |
=
| x-3 |
| x-2 |
| (x-2)(x+2)-5 |
| x-2 |
=
| x-3 |
| x-2 |
| x2-9 |
| x-2 |
=
| x-3 |
| x-2 |
| x-2 |
| (x+3)(x-3) |
=
| 1 |
| x+3 |
当x=
| 5 |
原式=
| 1 | ||
|
| 1 | ||
|
| ||
| 5 |
点评:本题考查了分式的混合运算和求值的应用,主要考查学生的化简和计算能力.
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