题目内容
化简求值:(a+b)2-(a+b)(a-b)-2b(2a+b),其中a=
,b=
.
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| 1 |
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(a+b)2-(a+b)(a-b)-2b(2a+b),
=a2+2ab+b2-(a2-b2)-4ab-2b2,
=a2+2ab+b2-a2+b2-4ab-2b2,
=-2ab,
当a=
,b=
时,
原式=-2ab=-2×
×
=-
.
=a2+2ab+b2-(a2-b2)-4ab-2b2,
=a2+2ab+b2-a2+b2-4ab-2b2,
=-2ab,
当a=
| 5 |
| 1 |
| 2 |
原式=-2ab=-2×
| 5 |
| 1 |
| 2 |
| 5 |
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