题目内容
先分解因式,再计算求值.
(1)当x=1时,(2x-1)2(3x+2)+(2x-1)(3x+2)2-x(1-2x)•(3x+2)=
(2)当x=0.4,m=5.5时,5x(m-2)-4x(m-2)=
(1)当x=1时,(2x-1)2(3x+2)+(2x-1)(3x+2)2-x(1-2x)•(3x+2)=
35
35
;(2)当x=0.4,m=5.5时,5x(m-2)-4x(m-2)=
1.4
1.4
.分析:(1)提取(2x-1)(3x+2),再代入求值;
(2)提取m-2,再代入求解.
(2)提取m-2,再代入求解.
解答:解:(1)原式=(2x-1)2(3x+2)+(2x-1)(3x+2)2+x(2x-1)(3x+2)
=(2x-1)(3x+2)(2x-1+3x+2+x)=(2x-1)(3x+2)(6x+1)
当x=1时,原式=(2-1)(3+2)(6+1)=1×5×7=35;
(2)原式=5x(m-2)-4x(m-2)=(m-2)(5x-4x)=(m-2)x
当x=0.4,m=5.5时,原式=0.4×(5.5-2)=0.4×3.5=1.4.
=(2x-1)(3x+2)(2x-1+3x+2+x)=(2x-1)(3x+2)(6x+1)
当x=1时,原式=(2-1)(3+2)(6+1)=1×5×7=35;
(2)原式=5x(m-2)-4x(m-2)=(m-2)(5x-4x)=(m-2)x
当x=0.4,m=5.5时,原式=0.4×(5.5-2)=0.4×3.5=1.4.
点评:两道题都是用到了提取公因式法分解因式,(1)题注意1-2x=-(2x-1).
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