题目内容
因式分
(1)ax2+2a2x+a3;
(2)(x+1)(2x-1)-(2x-1)2.
(1)ax2+2a2x+a3;
(2)(x+1)(2x-1)-(2x-1)2.
(1)ax2+2a2x+a3
=a(x2+2ax+a2)
=a(x+a)2;
(2)(x+1)(2x-1)-(2x-1)2
=(2x-1)[(x+1)-(2x-1)]
=(2x-1)(x+1-2x+1)
=(2x-1)(-x+2)
=-(2x-1)(x-2).
=a(x2+2ax+a2)
=a(x+a)2;
(2)(x+1)(2x-1)-(2x-1)2
=(2x-1)[(x+1)-(2x-1)]
=(2x-1)(x+1-2x+1)
=(2x-1)(-x+2)
=-(2x-1)(x-2).
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