题目内容
(1)计算:
+(
)-1-4cos45°-2÷
(2)解方程:x2-2x-2=0.
| 8 |
| 1 |
| 2 |
| 1 |
| 2 |
(2)解方程:x2-2x-2=0.
(1)原式=2
+2-4×
-4,
=2
+2-2
-4,
=-2;
(2)移项,得
x2-2x=2,
配方,得
x2-2x+1=2+1,即(x-1)2=3,
开方,得
x-1=±
,
解得,x1=1+
,x2=1-
.
| 2 |
| ||
| 2 |
=2
| 2 |
| 2 |
=-2;
(2)移项,得
x2-2x=2,
配方,得
x2-2x+1=2+1,即(x-1)2=3,
开方,得
x-1=±
| 3 |
解得,x1=1+
| 3 |
| 3 |
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