题目内容
先化简,再求值:| x+1 |
| x2-1 |
| x2+x |
| x+1 |
| 2 |
分析:先将分式的分子与分母分解因式,再约分,化简后再代入求值即可.
解答:解:
•
-1=
•
-1
=
-1
=
-
=
=
,
当x=
+1时,
原式=
=
=
.
| x+1 |
| x2-1 |
| x2+x |
| x+1 |
| x+1 |
| (x+1)(x-1) |
| x(x+1) |
| x+1 |
=
| x |
| x-1 |
=
| x |
| x-1 |
| x-1 |
| x-1 |
=
| x-x+1 |
| x-1 |
=
| 1 |
| x-1 |
当x=
| 2 |
原式=
| 1 |
| x-1 |
=
| 1 | ||
|
=
| ||
| 2 |
点评:本题考查了分式的化简求值,解答此题的关键是把分式化到最简,然后代值计算.
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