题目内容
若| 2m+n |
| n |
| 4 |
| 3 |
| m |
| n |
分析：根据分式的除法法则
=2×
+1，即可解答．
| 2m+n |
| n |
| m |
| n |
解答：解：∵
=
∴2
+1=
∴
=
．
故答案为
．
| 2m+n |
| n |
| 4 |
| 3 |
∴2
| m |
| n |
| 4 |
| 3 |
∴
| m |
| n |
| 1 |
| 6 |
故答案为
| 1 |
| 6 |
点评：解答本题不仅要会通分，还要将
当做一个整体看待．
| m |
| n |
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题目内容
若| 2m+n |
| n |
| 4 |
| 3 |
| m |
| n |
| 2m+n |
| n |
| m |
| n |
| 2m+n |
| n |
| 4 |
| 3 |
| m |
| n |
| 4 |
| 3 |
| m |
| n |
| 1 |
| 6 |
| 1 |
| 6 |
| m |
| n |