题目内容
化简求值(x+y)(x-y)+(x-y)2-(6x2y-2xy2)÷(2y),其中x=-2,y=
;
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(x+y)(x-y)+(x-y)2-(6x2y-2xy2)÷(2y),
=x2-y2+x2-2xy+y2-3x2+xy,
=-x2-xy,
当x=-2,y=
时,
原式=-(-2)2-(-2)×
=-4+
=-
.
=x2-y2+x2-2xy+y2-3x2+xy,
=-x2-xy,
当x=-2,y=
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原式=-(-2)2-(-2)×
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| 10 |
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