题目内容
(1)
;
(2)
;
(3)
;
(4)
;
(5)﹣3﹣[﹣5﹣0.2÷
×(﹣2)2].
(2)
(3)
(4)
(5)﹣3﹣[﹣5﹣0.2÷
解:(1)
;
=1﹣
=
;
(2)
;
=(
)×
=
;
(3)
,
=﹣8﹣4+12
=0;
(4)
,
=﹣1﹣
×(﹣7)
=
(5)﹣3﹣[﹣5﹣0.2÷
×(﹣2)2],
=﹣3﹣[﹣5﹣
×4]
=﹣3﹣(﹣6)
=3.
=1﹣
=
(2)
=(
=
(3)
=﹣8﹣4+12
=0;
(4)
=﹣1﹣
=
(5)﹣3﹣[﹣5﹣0.2÷
=﹣3﹣[﹣5﹣
=﹣3﹣(﹣6)
=3.
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