题目内容
计算:
(1)
-
+
(2)
÷
×
(3)(
-5
)×
(4)(1-
)2-
.
(1)
| 8 |
| 2 |
| 1 |
| 5 |
| 50 |
(2)
| 1 |
| 2 |
3
|
2
|
1
|
(3)(
|
| 3 |
| 6 |
(4)(1-
| 2 |
| ||||
|
分析:(1)首先化简二次根式,进而合并同类项即可;
(2)直接根据二次根式的乘除运算法则得出即可;
(3)首先化简二次根式,再根据二次根式的乘除运算法则得出即可;
(4)首先利用完全平方公式去括号,进而合并同类项得出即可.
(2)直接根据二次根式的乘除运算法则得出即可;
(3)首先化简二次根式,再根据二次根式的乘除运算法则得出即可;
(4)首先利用完全平方公式去括号,进而合并同类项得出即可.
解答:解:(1)(1)
-
+
=2
-
+
×5
=2
;
(2)
÷
×
=
=
;
(3)(
-5
)×
=(
-5
)×
=
-15
;
(4)(1-
)2-
=1+2-2
-(1-
)
=2-
.
| 8 |
| 2 |
| 1 |
| 5 |
| 50 |
| 2 |
| 2 |
| 1 |
| 5 |
| 2 |
| 2 |
(2)
| 1 |
| 2 |
3
|
2
|
1
|
=
| 1 |
| 2 |
|
=
| ||
| 2 |
(3)(
|
| 3 |
| 6 |
=(
2
| ||
| 9 |
| 3 |
| 6 |
=
| 4 |
| 3 |
| 2 |
(4)(1-
| 2 |
| ||||
|
=1+2-2
| 2 |
| 2 |
=2-
| 2 |
点评:此题主要考查了二次根式的混合运算,正确掌握运算法则是解题关键.
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