题目内容
计算.
(1)(-6)×(+8);
(2)(-0.36)×(-
);
(3)(-2
)×(-2
);
(4)(-288
)×0;
(5)2
×(-1
)×(-
)×(-
);
(6)(-5)×(-8)×0×(-10)×(-15);
(7)(-3
)×(-0.12)×(-2
)×33
;
(8)(+
)×|-
|×2
×(-5
);
(9)(-3)×(-4)×(-5)+(-5)×(-7);
(10)(-0.1)×(-1)×(-100)-0.01×(1000).
解:(1)(-6)×(+8),
=-(6×8),
=-48;
(2)(-0.36)×(-
),
=0.36×
,
=0.04×2.
=0.08;
(3)(-2
)×(-2
),
=
×
,
=6;
(4)(-288
)×0=0;
(5)2
×(-1
)×(-
)×(-
),
=-
×
×
×
,
=-3;
(6)(-5)×(-8)×0×(-10)×(-15)=0;
(7)(-3
)×(-0.12)×(-2
)×33
,
=-
×0.12×
×
,
=-30;
(8)(+
)×|-
|×2
×(-5
),
=
×
×
×(-
),
=-4;
(9)(-3)×(-4)×(-5)+(-5)×(-7),
=-3×4×5+5×7,
=-60+35,
=-25;
(10)(-0.1)×(-1)×(-100)-0.01×(1000),
=-0.1×1×100-0.01×1000,
=-10-10,
=-20.
分析:根据有理数的乘法法则进行运算,先判断出积的符号,再计算绝对值.
点评:此题考查了有理数的运算法则:①运用乘法法则,先确定符号,再把绝对值相乘.
②多个因数相乘,看0因数和积的符号当先,这样做使运算既准确又简单.
=-(6×8),
=-48;
(2)(-0.36)×(-
=0.36×
=0.04×2.
=0.08;
(3)(-2
=
=6;
(4)(-288
(5)2
=-
=-3;
(6)(-5)×(-8)×0×(-10)×(-15)=0;
(7)(-3
=-
=-30;
(8)(+
=
=-4;
(9)(-3)×(-4)×(-5)+(-5)×(-7),
=-3×4×5+5×7,
=-60+35,
=-25;
(10)(-0.1)×(-1)×(-100)-0.01×(1000),
=-0.1×1×100-0.01×1000,
=-10-10,
=-20.
分析:根据有理数的乘法法则进行运算,先判断出积的符号,再计算绝对值.
点评:此题考查了有理数的运算法则:①运用乘法法则,先确定符号,再把绝对值相乘.
②多个因数相乘,看0因数和积的符号当先,这样做使运算既准确又简单.
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