题目内容
(1)已知x=
+1,求(1-
)÷
的值.
(2)计算:2
(
+
)-
.
| 2 |
| 1 |
| x |
| x2-2x+1 |
| x |
(2)计算:2
| 2 |
| 2 |
| 1 | ||
|
| ||||
|
(1)原式=
÷
=
•
=
,
当x=
+1时,原式=
=
;
(2)原式=4+2-(3-2)
=6-1
=5.
| x-1 |
| x |
| (x-1)2 |
| x |
| x-1 |
| x |
| x |
| (x-1)2 |
| 1 |
| x-1 |
当x=
| 2 |
| 1 | ||
|
| ||
| 2 |
(2)原式=4+2-(3-2)
=6-1
=5.
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