题目内容
已知一元二次方程x2-2x-1=0的两根是x1,x2,则
+
=( )
| 1 |
| x1 |
| 1 |
| x2 |
A.
| B.2 | C.-
| D.-2 |
根据根与系数的关系:x1+x2=2,x1•x2=-1.
则
+
=
=
=-2.故选D
则
| 1 |
| x1 |
| 1 |
| x2 |
| x1+x2 |
| x1•x2 |
| 2 |
| -1 |
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题目内容
| 1 |
| x1 |
| 1 |
| x2 |
A.
| B.2 | C.-
| D.-2 |
| 1 |
| x1 |
| 1 |
| x2 |
| x1+x2 |
| x1•x2 |
| 2 |
| -1 |