题目内容
先化简(| x+1 |
| x-1 |
| 1 |
| x2-2x+1 |
| x |
| x-1 |
分析:先对x2-2x+1分解因式,再进行通分化简,最后求值.
解答:解:(
+
)÷
=
×
=
,(x≠1)
当x=2时,
原式=2.
| x+1 |
| x-1 |
| 1 |
| x2-2x+1 |
| x |
| x-1 |
=
| x2-1+1 |
| (x-1)2 |
| x-1 |
| x |
=
| x |
| x-1 |
当x=2时,
原式=2.
点评:主要考查分式的化简求值比较简单,不过选择喜欢的值时,一定要使分母有意义.
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