题目内容
先化简,再求值:
(1)(
-
)•
,其中x=
-2
(2)(x-2-
)÷
,其中x=
-3.
(1)(
| 3x |
| x-1 |
| x |
| x+1 |
| x2-1 |
| x |
| 2 |
(2)(x-2-
| 5 |
| x+2 |
| x-3 |
| 2x+4 |
| 2 |
分析:(1)(2)先根据分式混合运算的法则把原式进行化简,再把x的值代入求解即可.
解答:解:(1)解一:原式=[
-
]•
=
•
=
•
=
•
=2(x+2)
当x=
-2时,原式=2(
-2+2)=2
解二:原式=
•
-
•
=
•
-
•
=3(x+1)-(x-1)
=3x+3-x+1
=2x+4
当x=
-2时,原式=2(
-2)+4=2
.
(2)原式=(
-
)•
=
•
=
•
=2x+6.
当x=
-3时,原式=2(
-3)+6=2
.
| 3x(x+1) |
| (x-1)(x+1) |
| x(x-1) |
| (x-1)(x+1) |
| x2-1 |
| x |
=
| 3x2+3x-x2+x |
| (x-1)(x+1) |
| x2-1 |
| x |
=
| 2x2+4x |
| (x+1)(x-1) |
| x2-1 |
| x |
=
| 2x(x +2) |
| (x+1)(x-1) |
| (x+1)(x-1) |
| x |
=2(x+2)
当x=
| 2 |
| 2 |
| 2 |
解二:原式=
| 3x |
| x-1 |
| x2-1 |
| x |
| x |
| x+1 |
| x2-1 |
| x |
=
| 3x |
| x-1 |
| (x-1)(x+1) |
| x |
| x |
| x+1 |
| (x-1x+1) |
| x |
=3(x+1)-(x-1)
=3x+3-x+1
=2x+4
当x=
| 2 |
| 2 |
| 2 |
(2)原式=(
| x2-4 |
| x+2 |
| 5 |
| x+2 |
| 2(x+2) |
| x-3 |
=
| x2-9 |
| x+2 |
| 2(x+2) |
| x-3 |
=
| (x+3)(x-3) |
| x+2 |
| 2(x+2) |
| x-3 |
=2x+6.
当x=
| 2 |
| 2 |
| 2 |
点评:本题考查的是分式的化简求值,在解答此类题目时要注意通分、分解因式、约分等知识点的灵活运用.
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