题目内容
先化简,再求值:3(a-1)2-(2a+1)(a-2),其中a=-
.
| 3 |
| 4 |
3(a-1)2-(2a+1)(a-2)
=3(a2-2a+1)-(2a2-4a+a-2)
=3a2-6a+3-2a2+3a+2
=a2-3a+5,
当a=-
时,原式=(-
)2-3×(-
)+5=
+
+5=
.
=3(a2-2a+1)-(2a2-4a+a-2)
=3a2-6a+3-2a2+3a+2
=a2-3a+5,
当a=-
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
| 9 |
| 16 |
| 9 |
| 4 |
| 125 |
| 16 |
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