题目内容
计算:(1)
| 3 | (-3)3 |
(2)
| 4 |
| 225 |
| 100 |
(3)
| 3 |
| ||
| 5 |
| 2 |
| 3 | -
| ||
| 3 | -343 |
| 3 | -27 |
(4)|2
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
分析:本题涉及二次根式化简、立方根、绝对值等考点,在计算时,需要针对每个考点分别进行计算,然后根据实数的运算法则求得计算结果.
解答:解:(1)原式=-3-1=-4;
(2)原式=2+15-10=7;
(3)原式=
-
×(-
)-(-7)-(-3),
=
+
+7+3,
=11;
(4)原式=5
-2
-(3
-2
),
=5
-2
-3
+2
,
=7
-5
,
=7×1.732-5×1.414,
=12.124-7.07,
=5.054,
≈5.1.
(2)原式=2+15-10=7;
(3)原式=
| 1 |
| 2 |
| 5 |
| 2 |
| 1 |
| 5 |
=
| 1 |
| 2 |
| 1 |
| 2 |
=11;
(4)原式=5
| 3 |
| 2 |
| 2 |
| 3 |
=5
| 3 |
| 2 |
| 2 |
| 3 |
=7
| 3 |
| 2 |
=7×1.732-5×1.414,
=12.124-7.07,
=5.054,
≈5.1.
点评:本题考查实数的综合运算能力,是各地中考题中常见的计算题型.解决此类题目的关键是熟练掌握二次根式化简、立方根、绝对值等考点的计算,计算时一定要认真.
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