题目内容
先化简代数式,再代入求值.(
+1)÷(1-
)×
,其中x=
.
| x |
| x+1 |
| 3x2 |
| 1-x2 |
| 1 |
| x-1 |
| ||
| 4 |
分析:先把括号内通分得到原式=
÷
•
,再把除法运算转化为乘法运算和把各分式的分子和分母因式分解得
•
•
,约分后得到原式=
,
接着把x的值代入得到原式=
,再进行分母有理化即可.
| x+x+1 |
| x+1 |
| 1-x2-3x2 |
| 1-x2 |
| 1 |
| x-1 |
| 2x+1 |
| x+1 |
| (x+1)(x-1) |
| (2x+1)(2x-1) |
| 1 |
| x-1 |
| 1 |
| 2x-1 |
接着把x的值代入得到原式=
| 1 | ||||
2×
|
解答:解:原式=
÷
•
=
•
•
=
,
当x=
时,原式=
=
=
-2.
| x+x+1 |
| x+1 |
| 1-x2-3x2 |
| 1-x2 |
| 1 |
| x-1 |
=
| 2x+1 |
| x+1 |
| (x+1)(x-1) |
| (2x+1)(2x-1) |
| 1 |
| x-1 |
=
| 1 |
| 2x-1 |
当x=
| ||
| 4 |
| 1 | ||||
2×
|
| 2 | ||
|
| 6 |
点评:本题考查了分式的化简求值:先把括号内通分,再把除法运算转化为乘法运算和把各分式的分子或分母因式分解,然后进行约分得到最简分式或整式,最后把满足条件的字母的值代入进行计算.
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